1988 WTA German Open – Doubles
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| Doubles | |
|---|---|
| 1988 WTA German Open | |
| 1987 Champions | |
| Final | |
| Champions | |
| Runners-up | |
| Score | 6–2, 4–6, 6–4 |
| Details | |
| Draw | 28 |
| Seeds | 8 |
| Events | |
1988 tennis event results
Claudia Kohde-Kilsch and Helena Suková were the defending champions but lost in the final 6–2, 4–6, 6–4 against Isabelle Demongeot and Nathalie Tauziat.[1]
Seeds
[edit ]Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated. The top four seeded teams received byes into the second round.
- West Germany Claudia Kohde-Kilsch / Czechoslovakia Helena Suková (final)
- Australia Hana Mandlíková / West Germany Eva Pfaff (second round)
- Czechoslovakia Jana Novotná / Argentina Mercedes Paz (quarterfinals)
- Netherlands Manon Bollegraf / Denmark Tine Scheuer-Larsen (quarterfinals)
- France Isabelle Demongeot / France Nathalie Tauziat (champions)
- Australia Jenny Byrne / Australia Janine Tremelling (quarterfinals)
- United States Kathleen Horvath / South Africa Dianne Van Rensburg (semifinals)
- United Kingdom Jo Durie / Australia Nicole Provis (semifinals)
Draw
[edit ]Key
[edit ]- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
Final
[edit ] Final
Top half
[edit ] First round
Second round
Quarterfinals
Semifinals
3
2
1
6
6
6
6
6
1
6
6
2
4
4
1
7
4
Bottom half
[edit ] First round
Second round
Quarterfinals
Semifinals
2
4
7
6
4
6
5
6
4
6
5
6
6
0
6
3
5
6
6
6
6
6
0
3
7
2
4
5
4
6
7
1
4
2
6
7
2
6
2
6
References
[edit ]- ^ John Barrett, ed. (1989). The International Tennis Federation : World of Tennis 1989. London: Willow Books. pp. 174, 194–195. ISBN 9780002183116.