1988 Virginia Slims of Arizona – Singles
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| Singles | |
|---|---|
| 1988 Virginia Slims of Arizona | |
| 1987 Champion | United States Anne White |
| Final | |
| Champion | Bulgaria Manuela Maleeva |
| Runner-up | South Africa Dianne Van Rensburg |
| Score | 6–3, 4–6, 6–2 |
| Events | |
1988 tennis event results
Anne White was the defending champion but lost in the first round to Elly Hakami.
Manuela Maleeva won in the final 6–3, 4–6, 6–2 against Dianne Van Rensburg.
Seeds
[edit ]A champion seed is indicated in bold text while text in italics indicates the round in which that seed was eliminated.
- Bulgaria Manuela Maleeva (champion)
- United States Patty Fendick (second round)
- Brazil Neige Dias (second round)
- South Africa Rosalyn Fairbank (quarterfinals)
- Australia Dianne Balestrat (first round)
- United States Peanut Louie-Harper (first round)
- n/a
- United States Terry Phelps (quarterfinals)
Draw
[edit ]Key
[edit ]- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
First round
Second round
Quarterfinals
Semifinals
Final
2
United States P Fendick
6
7
6