1988 Internationaux de Strasbourg – Singles
Appearance
From Wikipedia, the free encyclopedia
Singles | |
---|---|
1988 Internationaux de Strasbourg | |
1987 Champion | Canada Carling Bassett |
Final | |
Champion | Italy Sandra Cecchini |
Runner-up | Austria Judith Wiesner |
Score | 6–3, 6–0 |
Details | |
Draw | 32 |
Seeds | 8 |
Events | |
1988 tennis event results
Carling Bassett was the defending champion but did not compete that year.
Sandra Cecchini won in the final 6–3, 6–0 against Judith Wiesner.[1] [2]
Seeds
[edit ]A champion seed is indicated in bold text while text in italics indicates the round in which that seed was eliminated.
- Soviet Union Natasha Zvereva (semifinals)
- Italy Sandra Cecchini (champion)
- United States Stephanie Rehe (second round)
- Canada Helen Kelesi (second round)
- Australia Anne Minter (quarterfinals)
- Soviet Union Leila Meskhi (second round)
- West Germany Isabel Cueto (second round)
- United States Elly Hakami (first round)
Draw
[edit ]Key
[edit ]- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
First round
Second round
Quarterfinals
Semifinals
Final
1
Soviet Union N Zvereva
6
7
2
Italy S Cecchini
6
6
References
[edit ]- ^ John Barrett, ed. (1989). The International Tennis Federation : World of Tennis 1989. London: Willow Books. pp. 174, 212. ISBN 9780002183116.
- ^ Henlon, Maureen; Bloch Shallouf, Renee, eds. (1988). 1988 Women's International Tennis Association Media Guide. Miami: WITA. p. 355.