1988 Virginia Slims of Oklahoma – Singles
From Wikipedia, the free encyclopedia
| Singles | |
|---|---|
| 1988 Virginia Slims of Oklahoma | |
| 1987 Champion | Australia Elizabeth Smylie |
| Final | |
| Champion | United States Lori McNeil |
| Runner-up | Netherlands Brenda Schultz |
| Score | 6–3, 6–2 |
| Details | |
| Draw | 32 |
| Seeds | 8 |
| Events | |
1988 tennis event results
The following is the result of the 1988 Virginia Slims of Oklahoma singles.
Elizabeth Smylie was the defending champion but did not compete that year.
Lori McNeil won in the final 6–3, 6–2 against Brenda Schultz.
Seeds
[edit ]A champion seed is indicated in bold text while text in italics indicates the round in which that seed was eliminated.
- United States Lori McNeil (champion)
- Bulgaria Katerina Maleeva (first round)
- Italy Raffaella Reggi (semifinals)
- Sweden Catarina Lindqvist (semifinals)
- Australia Dianne Balestrat (first round)
- Canada Helen Kelesi (quarterfinals)
- Czechoslovakia Jana Novotná (quarterfinals)
- United States Kathleen Horvath (first round)
Draw
[edit ]Key
[edit ]- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
First round
Second round
Quarterfinals
Semifinals
Final
1
United States L McNeil
1
6
6