How i make the code skip to a certain point in a if-statement

Question

I'm working on a basic game. I'd like to know how I can make the code go to a specific point in the code/if-statement, rather than starting off at the beginning.

For example, in my code at line 19: kithcen() I don't want to redirect it to the start of the if-statement; again going on the describe the kitchen and then asking for an input: choice02 = raw_input("What do you do?"), but rather i want it to directly skip to the input part.

def kitchen():
 print "You see a dusty old kitchen, nobody has probably used it for quite a while."
 print "There are 3 different cupboards(0, 1, 2) or a letter(3) placed on the counter."
 choice02 = raw_input("What do you do? >")
 if choice02 == "0" or choice02 == "first cupboard" or choice02 == "check first cupboard" or choice02 == "open first cupboard":
 print "You see a dusty empty bottles of milks, with spiderwebs at the corners of the cupboard. Nothing of Interest here."
 raw_input(">")
 kitchen()
 elif choice02 == "1" or choice02 == "second cupbaord" or choice02 == "check second cupboard" or choice02 == "open second cupboard":
 print "You see some packs of likely expired cereal and a key(0)."
 choice_02_A = raw_input("What do you do? >")
 #----------------------------------------------------------------------------------------------------------#
 if choice02_A == "pick key" or choice02_A == "key" or choice02_A == "0" or choice02_A == "get key":
 print "You picked the key. This probably unlocks some door."
 raw_input("> ")
 kitchen()
 elif choice02_A == "close cupboard" or choice02_A == "kitchen" or choice02_A == "go back to kitchen":
 kitchen()
 else:
 print "Not a valid option."
 #-----------------------------------------------------------------------------------------------------------#
 elif choice02 == "2" or choice02 == "third cupboard" or choice02 == "check third cupboard" or choice02 == "open third cupboard":
 print "You see an empty or dusty cupboard. Nothing of interest here."
 raw_input("> ")
 kitchen()
 elif choice02 == "3" or choice02 == "check letter" or choice02 == "letter" or choice02 == "read letter":
 print """
 You read the letter:
 \n"Dear Shawn............\n"
 It makes no sense to you.
 """
 elif choice02 == "go back" or choice02 == "entrance hall" or choice02 == "go to entrance hall":
 entrance_hall()
else:
 "Not a valid Option."

• Mad Physicist: Indent your code properly
• Mad Physicist: Also, you keep saying "loop" in your question. What loop?
• Sarwan Shah: Sorry, my bad, I'm new. A misconception, anyways I made a edit. The indentation go messed up a bit while copying.
• Mad Physicist: No worries. Also, please indent. The code as it stands is not valid Python. Specifically, everything after def needs to be up one level.

Answer 1

I see no loop, but if you only want the print statements when you call the function from outside, you could have an optional boolean like this:

def kitchen(already_there=False):
 if not already_there:
 print('...')
 choice02 = raw_input("What do you do? >")
 # ...
 elif # ...
 # ...
 kitchen(already_there=True)

• Mad Physicist: This is especially nice because it is backwards compatible with any code you've already written.

Answer 2

You might want to consider refactoring your code and using dictionaries to avoid long if-else statements.

See https://stackoverflow.com/a/27365077/2884613.

print "There are 3 different cupboards(0, 1, 2) or a letter(3) placed on the counter." 
alias = {
 '0': '0',
 'first cupboard': '0',
 'check first cupboard': '0',
 'open first cupboard': '0',
 '1': '1',
 'second cupboard': '1',
 'check second cupboard':'1',
 ...
}
dic = {
 "0":"You see a dusty empty bottles of milks, with spiderwebs at the corners of the cupboard. Nothing of Interest here.", \
 "1":"You see some packs of likely expired cereal and a key(0).", \
 "2":"You see an empty or dusty cupboard. Nothing of interest here."
 ...
}
while(True):
 choice02 = raw_input("What do you do? >")
 if choice02 in alias:
 print dic[alias[choice02]]
 break
 else:
 print "Not a valid option"

• Sarwan Shah: Alright, Thanks! This is definitely cleaner. Though how could I assign multiple keys to a single value/string
• raychz: Hmm, one possibility is to use two dictionaries. One to store the alias key association and one to store your actual data. I'll update my answer shortly.