conditional skip in python if

Question

i am trying for something like this

def scanthefile():
 x = 11
 if x > 5
 """ i want to come out of if and go to end of scanfile """
 print x
 return info

update:

if have to check for the content size of a file. and if the content size is larger than a value say 500 , then i should go to the end of the scanfile

• S.Lott: x = 11; if x > 5? That's always true. What's the point of this? Even with the update, the question makes very little sense. Can you rewrite this question so it does make sense? Could you -- for example -- delete the code that makes no sense?
• Kimvais: This question is a great example on how not to ask. You should have asked "how do I check for the content size of a file in python" in the first place - not pasting some arbitrary, partial attempt to do it without telling what you are trying to do.

Answer 1

If I understand your question, and I'm really unsure I do, you can just de-indent:

x = 11
if x > 5:
 pass # Your code goes here.
print x

Answer 2

By "go to the end of file", do you mean "seek to the end of file"? Then:

import os
 ...
if x > 5:
 thefile.seek(0, os.SEEK_END)

If you mean something completely different, you'd better clarify!

Answer 3

OK, so to answer your update:

import os
fn = 'somefile.txt'
thefile = open(fn, 'r')
# The next line check the size of the file. Replace "stat(fn).st_size" with your own code if you want.
if stat(fn).st_size > 500:
 thefile.seek(0, os.SEEK_END)
# you are now at the end of the file if the size is > 500

Answer 4

The way I understand the question is that you want to break out of an if-statement, which you can't.

You can however replace it with a while loop:

def scanthefile():
 x = 11
 while x > 5:
 # do something here...
 if CONTENTSIZE > 500:
 break
 # do something else..
 break # Which will make the while loop only run once.
 return info