Open mapping theorem (functional analysis)
In functional analysis, the open mapping theorem, also known as the Banach–Schauder theorem or the Banach theorem[1] (named after Stefan Banach and Juliusz Schauder), is a fundamental result that states that if a bounded or continuous linear operator between Banach spaces is surjective then it is an open map.
A special case is also called the bounded inverse theorem (also called inverse mapping theorem or Banach isomorphism theorem), which states that a bijective bounded linear operator {\displaystyle T} from one Banach space to another has bounded inverse {\displaystyle T^{-1}}.
Statement and proof
[edit ]Open mapping theorem—[2] [3] Let {\displaystyle T:E\to F} be a surjective continuous linear map between Banach spaces (or more generally Fréchet spaces). Then {\displaystyle T} is an open mapping (that is, if {\displaystyle U\subset E} is an open subset, then {\displaystyle T(U)} is open).
The proof here uses the Baire category theorem, and completeness of both {\displaystyle E} and {\displaystyle F} is essential to the theorem. The statement of the theorem is no longer true if either space is assumed to be only a normed vector space; see § Counterexample.
The proof is based on the following lemmas, which are also somewhat of independent interest. A linear map {\displaystyle f:E\to F} between topological vector spaces is said to be nearly open if, for each neighborhood {\displaystyle U} of zero, the closure {\displaystyle {\overline {f(U)}}} contains a neighborhood of zero. The next lemma may be thought of as a weak version of the open mapping theorem.
Lemma—[4] [5] A linear map {\displaystyle f:E\to F} between normed spaces is nearly open if the image of {\displaystyle f} is non-meager in {\displaystyle F}. (The continuity is not needed.)
Proof: Shrinking {\displaystyle U}, we can assume {\displaystyle U} is an open ball centered at zero. We have {\displaystyle f(E)=f\left(\bigcup _{n\in \mathbb {N} }nU\right)=\bigcup _{n\in \mathbb {N} }f(nU)}. Thus, some {\displaystyle {\overline {f(nU)}}} contains an interior point {\displaystyle y}; that is, for some radius {\displaystyle r>0},
- {\displaystyle B(y,r)\subset {\overline {f(nU)}}.}
Then for any {\displaystyle v} in {\displaystyle F} with {\displaystyle \|v\|<r}, by linearity, convexity and {\displaystyle (-1)U\subset U},
- {\displaystyle v=v-y+y\in {\overline {f(-nU)}}+{\overline {f(nU)}}\subset {\overline {f(2nU)}}},
which proves the lemma by dividing by {\displaystyle 2n}.{\displaystyle \square } (The same proof works if {\displaystyle E,F} are pre-Fréchet spaces.)
The completeness on the domain then allows to upgrade nearly open to open.
Lemma (Schauder)—[6] [7] Let {\displaystyle f:E\to F} be a continuous linear map between normed spaces.
If {\displaystyle f} is nearly-open and if {\displaystyle E} is complete, then {\displaystyle f} is open and surjective.
More precisely, if {\displaystyle B(0,\delta )\subset {\overline {f(B(0,1))}}} for some {\displaystyle \delta >0} and if {\displaystyle E} is complete, then
- {\displaystyle B(0,\delta )\subset f(B(0,1))}
where {\displaystyle B(x,r)} is an open ball with radius {\displaystyle r} and center {\displaystyle x}.
Proof: Let {\displaystyle y} be in {\displaystyle B(0,\delta )} and {\displaystyle c_{n}>0} some sequence. We have: {\displaystyle {\overline {B(0,\delta )}}\subset {\overline {f(B(0,1))}}}. Thus, for each {\displaystyle \epsilon >0} and {\displaystyle z} in {\displaystyle F}, we can find an {\displaystyle x} with {\displaystyle \|x\|<\delta ^{-1}\|z\|} and {\displaystyle z} in {\displaystyle B(f(x),\epsilon )}. Thus, taking {\displaystyle z=y}, we find an {\displaystyle x_{1}} such that
- {\displaystyle \|y-f(x_{1})\|<c_{1},,円\|x_{1}\|<\delta ^{-1}\|y\|.}
Applying the same argument with {\displaystyle z=y-f(x_{1})}, we then find an {\displaystyle x_{2}} such that
- {\displaystyle \|y-f(x_{1})-f(x_{2})\|<c_{2},,円\|x_{2}\|<\delta ^{-1}c_{1}}
where we observed {\displaystyle \|x_{2}\|<\delta ^{-1}\|z\|<\delta ^{-1}c_{1}}. Then so on. Thus, if {\displaystyle c:=\sum c_{n}<\infty }, we found a sequence {\displaystyle x_{n}} such that {\displaystyle x=\sum _{1}^{\infty }x_{n}} converges and {\displaystyle f(x)=y}. Also,
- {\displaystyle \|x\|\leq \sum _{1}^{\infty }\|x_{n}\|\leq \delta ^{-1}\|y\|+\delta ^{-1}c.}
Since {\displaystyle \delta ^{-1}\|y\|<1}, by making {\displaystyle c} small enough, we can achieve {\displaystyle \|x\|<1}. {\displaystyle \square } (Again the same proof is valid if {\displaystyle E,F} are pre-Fréchet spaces.)
Proof of the theorem: By Baire's category theorem, the first lemma applies. Then the conclusion of the theorem follows from the second lemma. {\displaystyle \square }
In general, a continuous bijection between topological spaces is not necessarily a homeomorphism. The open mapping theorem, when it applies, implies the bijectivity is enough:
Corollary (Bounded inverse theorem)—[8] A continuous bijective linear operator between Banach spaces (or Fréchet spaces) has continuous inverse. That is, the inverse operator is continuous.
Even though the above bounded inverse theorem is a special case of the open mapping theorem, the open mapping theorem in turns follows from that. Indeed, a surjective continuous linear operator {\displaystyle T:E\to F} factors as
- {\displaystyle T:E{\overset {p}{\to }}E/\operatorname {ker} T{\overset {T_{0}}{\to }}F.}
Here, {\displaystyle T_{0}} is continuous and bijective and thus is a homeomorphism by the bounded inverse theorem; in particular, it is an open mapping. As a quotient map for topological groups is open, {\displaystyle T} is open then.
Because the open mapping theorem and the bounded inverse theorem are essentially the same result, they are often simply called Banach's theorem.
Transpose formulation
[edit ]Here is a formulation of the open mapping theorem in terms of the transpose of an operator.
Theorem—[6] Let {\displaystyle X} and {\displaystyle Y} be Banach spaces, let {\displaystyle B_{X}} and {\displaystyle B_{Y}} denote their open unit balls, and let {\displaystyle T:X\to Y} be a bounded linear operator. If {\displaystyle \delta >0} then among the following four statements we have {\displaystyle (1)\implies (2)\implies (3)\implies (4)} (with the same {\displaystyle \delta })
- {\displaystyle \delta \left\|y'\right\|\leq \left\|T'y'\right\|} for all {\displaystyle y'\in Y'} = continuous dual of {\displaystyle Y};
- {\displaystyle \delta B_{Y}\subset {\overline {T\left(B_{X}\right)}}};
- {\displaystyle \delta B_{Y}\subset {T\left(B_{X}\right)}};
- {\displaystyle T} is surjective.
Furthermore, if {\displaystyle T} is surjective then (1) holds for some {\displaystyle \delta >0.}
Proof: The idea of 1. {\displaystyle \Rightarrow } 2. is to show: {\displaystyle y\notin {\overline {T(B_{X})}}\Rightarrow \|y\|>\delta ,} and that follows from the Hahn–Banach theorem. 2. {\displaystyle \Rightarrow } 3. is exactly the second lemma in § Statement and proof. Finally, 3. {\displaystyle \Rightarrow } 4. is trivial and 4. {\displaystyle \Rightarrow } 1. easily follows from the open mapping theorem. {\displaystyle \square }
Alternatively, 1. implies that {\displaystyle T'} is injective and has closed image and then by the closed range theorem, that implies {\displaystyle T} has dense image and closed image, respectively; i.e., {\displaystyle T} is surjective. Hence, the above result is a variant of a special case of the closed range theorem.
Quantative formulation
[edit ]Terence Tao gives the following quantitative formulation of the theorem:[9]
Theorem—Let {\displaystyle T:E\to F} be a bounded operator between Banach spaces. Then the following are equivalent:
- {\displaystyle T} is open.
- {\displaystyle T} is surjective.
- There exists a constant {\displaystyle C>0} such that, for each {\displaystyle f} in {\displaystyle F}, the equation {\displaystyle Tu=f} has a solution {\displaystyle u} with {\displaystyle \|u\|\leq C\|f\|}.
- 3. holds for {\displaystyle f} in some dense subspace of {\displaystyle F}.
Proof: 2. {\displaystyle \Rightarrow } 1. is the usual open mapping theorem.
1. {\displaystyle \Rightarrow } 4.: For some {\displaystyle r>0}, we have {\displaystyle B(0,2)\subset T(B(0,r))} where {\displaystyle B} means an open ball. Then {\displaystyle {\frac {f}{\|f\|}}=T\left({\frac {u}{\|f\|}}\right)} for some {\displaystyle {\frac {u}{\|f\|}}} in {\displaystyle B(0,r)}. That is, {\displaystyle Tu=f} with {\displaystyle \|u\|<r\|f\|}.
4. {\displaystyle \Rightarrow } 3.: We can write {\displaystyle f=\sum _{0}^{\infty }f_{j}} with {\displaystyle f_{j}} in the dense subspace and the sum converging in norm. Then, since {\displaystyle E} is complete, {\displaystyle u=\sum _{0}^{\infty }u_{j}} with {\displaystyle \|u_{j}\|\leq C\|f_{j}\|} and {\displaystyle Tu_{j}=f_{j}} is a required solution. Finally, 3. {\displaystyle \Rightarrow } 2. is trivial. {\displaystyle \square }
Counterexample
[edit ]The open mapping theorem may not hold for normed spaces that are not complete. A quickest way to see this is to note that the closed graph theorem, a consequence of the open mapping theorem, fails without completeness. But here is a more concrete counterexample. Consider the space X of sequences x : N → R with only finitely many non-zero terms equipped with the supremum norm. The map T : X → X defined by
- {\displaystyle Tx=\left(x_{1},{\frac {x_{2}}{2}},{\frac {x_{3}}{3}},\dots \right)}
is bounded, linear and invertible, but T−1 is unbounded. This does not contradict the bounded inverse theorem since X is not complete, and thus is not a Banach space. To see that it's not complete, consider the sequence of sequences x(n) ∈ X given by
- {\displaystyle x^{(n)}=\left(1,{\frac {1}{2}},\dots ,{\frac {1}{n}},0,0,\dots \right)}
converges as n → ∞ to the sequence x(∞) given by
- {\displaystyle x^{(\infty )}=\left(1,{\frac {1}{2}},\dots ,{\frac {1}{n}},\dots \right),}
which has all its terms non-zero, and so does not lie in X.
The completion of X is the space {\displaystyle c_{0}} of all sequences that converge to zero, which is a (closed) subspace of the lp space l∞(N), which is the space of all bounded sequences. However, in this case, the map T is not onto, and thus not a bijection. To see this, one need simply note that the sequence
- {\displaystyle x=\left(1,{\frac {1}{2}},{\frac {1}{3}},\dots \right),}
is an element of {\displaystyle c_{0}}, but is not in the range of {\displaystyle T:c_{0}\to c_{0}}. Same reasoning applies to show {\displaystyle T} is also not onto in {\displaystyle l^{\infty }}, for example {\displaystyle x=\left(1,1,1,\dots \right)} is not in the range of {\displaystyle T}.
Consequences
[edit ]The open mapping theorem has several important consequences:
- If {\displaystyle T:X\to Y} is a bijective continuous linear operator between the Banach spaces {\displaystyle X} and {\displaystyle Y,} then the inverse operator {\displaystyle T^{-1}:Y\to X} is continuous as well (this is called the bounded inverse theorem).[10]
- If {\displaystyle T:X\to Y} is a linear operator between the Banach spaces {\displaystyle X} and {\displaystyle Y,} and if for every sequence {\displaystyle \left(x_{n}\right)} in {\displaystyle X} with {\displaystyle x_{n}\to 0} and {\displaystyle Tx_{n}\to y} it follows that {\displaystyle y=0,} then {\displaystyle T} is continuous (the closed graph theorem).[11]
- Given a bounded operator {\displaystyle T:E\to F} between normed spaces, if the image of {\displaystyle T} is non-meager and if {\displaystyle E} is complete, then {\displaystyle T} is open and surjective and {\displaystyle F} is complete (to see this, use the two lemmas in the proof of the theorem).[12]
- An exact sequence of Banach spaces (or more generally Fréchet spaces) is topologically exact.
- The closed range theorem, which says an operator (under some assumption) has closed image if and only if its transpose has closed image (see closed range theorem#Sketch of proof).
The open mapping theorem does not imply that a continuous surjective linear operator admits a continuous linear section. What we have is:[9]
- A surjective continuous linear operator between Banach spaces admits a continuous linear section if and only if the kernel is topologically complemented.
In particular, the above applies to an operator between Hilbert spaces or an operator with finite-dimensional kernel (by the Hahn–Banach theorem). If one drops the requirement that a section be linear, a surjective continuous linear operator between Banach spaces admits a continuous section; this is the Bartle–Graves theorem.[13] [14]
Generalizations
[edit ]Local convexity of {\displaystyle X} or {\displaystyle Y} is not essential to the proof, but completeness is: the theorem remains true in the case when {\displaystyle X} and {\displaystyle Y} are F-spaces. Furthermore, the theorem can be combined with the Baire category theorem in the following manner:
Open mapping theorem for continuous maps[12] [15] —Let {\displaystyle A:X\to Y} be a continuous linear operator from a complete pseudometrizable TVS {\displaystyle X} onto a Hausdorff TVS {\displaystyle Y.} If {\displaystyle \operatorname {Im} A} is nonmeager in {\displaystyle Y} then {\displaystyle A:X\to Y} is a (surjective) open map and {\displaystyle Y} is a complete pseudometrizable TVS. Moreover, if {\displaystyle X} is assumed to be hausdorff (i.e. a F-space), then {\displaystyle Y} is also an F-space.
(The proof is essentially the same as the Banach or Fréchet cases; we modify the proof slightly to avoid the use of convexity,)
Furthermore, in this latter case if {\displaystyle N} is the kernel of {\displaystyle A,} then there is a canonical factorization of {\displaystyle A} in the form {\displaystyle X\to X/N{\overset {\alpha }{\to }}Y} where {\displaystyle X/N} is the quotient space (also an F-space) of {\displaystyle X} by the closed subspace {\displaystyle N.} The quotient mapping {\displaystyle X\to X/N} is open, and the mapping {\displaystyle \alpha } is an isomorphism of topological vector spaces.[16]
An important special case of this theorem can also be stated as
Theorem[17] —Let {\displaystyle X} and {\displaystyle Y} be two F-spaces. Then every continuous linear map of {\displaystyle X} onto {\displaystyle Y} is a TVS homomorphism, where a linear map {\displaystyle u:X\to Y} is a topological vector space (TVS) homomorphism if the induced map {\displaystyle {\hat {u}}:X/\ker(u)\to Y} is a TVS-isomorphism onto its image.
On the other hand, a more general formulation, which implies the first, can be given:
Open mapping theorem[15] —Let {\displaystyle A:X\to Y} be a surjective linear map from a complete pseudometrizable TVS {\displaystyle X} onto a TVS {\displaystyle Y} and suppose that at least one of the following two conditions is satisfied:
- {\displaystyle Y} is a Baire space, or
- {\displaystyle X} is locally convex and {\displaystyle Y} is a barrelled space,
If {\displaystyle A} is a closed linear operator then {\displaystyle A} is an open mapping. If {\displaystyle A} is a continuous linear operator and {\displaystyle Y} is Hausdorff then {\displaystyle A} is (a closed linear operator and thus also) an open mapping.
Nearly/Almost open linear maps
A linear map {\displaystyle A:X\to Y} between two topological vector spaces (TVSs) is called a nearly open map (or sometimes, an almost open map ) if for every neighborhood {\displaystyle U} of the origin in the domain, the closure of its image {\displaystyle \operatorname {cl} A(U)} is a neighborhood of the origin in {\displaystyle Y.}[18] Many authors use a different definition of "nearly/almost open map" that requires that the closure of {\displaystyle A(U)} be a neighborhood of the origin in {\displaystyle A(X)} rather than in {\displaystyle Y,}[18] but for surjective maps these definitions are equivalent. A bijective linear map is nearly open if and only if its inverse is continuous.[18] Every surjective linear map from locally convex TVS onto a barrelled TVS is nearly open.[19] The same is true of every surjective linear map from a TVS onto a Baire TVS.[19]
Open mapping theorem[20] —If a closed surjective linear map from a complete pseudometrizable TVS onto a Hausdorff TVS is nearly open then it is open.
Theorem[21] —If {\displaystyle A:X\to Y} is a continuous linear bijection from a complete Pseudometrizable topological vector space (TVS) onto a Hausdorff TVS that is a Baire space, then {\displaystyle A:X\to Y} is a homeomorphism (and thus an isomorphism of TVSs).
Webbed spaces are a class of topological vector spaces for which the open mapping theorem and the closed graph theorem hold.
See also
[edit ]- Closed graph – Graph of a map closed in the product spacePages displaying short descriptions of redirect targets
- Closed graph theorem – Theorem relating continuity to graphs
- Closed graph theorem (functional analysis) – Theorems connecting continuity to closure of graphs
- Open mapping theorem (complex analysis) – Theorem that holomorphic functions on complex domains are open mapsPages displaying wikidata descriptions as a fallback
- Surjection of Fréchet spaces – Characterization of surjectivity
- Ursescu theorem – Generalization of closed graph, open mapping, and uniform boundedness theorem
- Webbed space – Space where open mapping and closed graph theorems hold
References
[edit ]- ^ Trèves 2006, p. 166.
- ^ Rudin 1973, Theorem 2.11.
- ^ Vogt 2000, Theorem 1.6.
- ^ Vogt 2000, Lemma 1.4.
- ^ The first part of the proof of Rudin 1991, Theorem 2.11.
- ^ a b Rudin 1991, Theorem 4.13.
- ^ Vogt 2000, Lemma 1.5.
- ^ Vogt 2000, Corollary 1.7.
- ^ a b Tao, Terence (February 1, 2009). "245B, Notes 9: The Baire category theorem and its Banach space consequences". What's New.
- ^ Rudin 1973, Corollary 2.12.
- ^ Rudin 1973, Theorem 2.15.
- ^ a b Rudin 1991, Theorem 2.11.
- ^ Sarnowski, Jarek (October 31, 2020). "Can the inverse operator in Bartle-Graves theorem be linear?". MathOverflow.
- ^ Borwein, J. M.; Dontchev, A. L. (2003). "On the Bartle–Graves theorem". Proceedings of the American Mathematical Society. 131 (8): 2553–2560. doi:10.1090/S0002-9939年03月07日229-0. hdl:1959.13/940334 . MR 1974655.
- ^ a b Narici & Beckenstein 2011, p. 468.
- ^ Dieudonné 1970, 12.16.8.
- ^ Trèves 2006, p. 170
- ^ a b c Narici & Beckenstein 2011, pp. 466.
- ^ a b Narici & Beckenstein 2011, pp. 467.
- ^ Narici & Beckenstein 2011, pp. 466−468.
- ^ Narici & Beckenstein 2011, p. 469.
Bibliography
[edit ]- Adasch, Norbert; Ernst, Bruno; Keim, Dieter (1978). Topological Vector Spaces: The Theory Without Convexity Conditions. Lecture Notes in Mathematics. Vol. 639. Berlin New York: Springer-Verlag. ISBN 978-3-540-08662-8. OCLC 297140003.
- Banach, Stefan (1932). Théorie des Opérations Linéaires [Theory of Linear Operations] (PDF). Monografie Matematyczne (in French). Vol. 1. Warszawa: Subwencji Funduszu Kultury Narodowej. Zbl 0005.20901. Archived from the original (PDF) on 2014年01月11日. Retrieved 2020年07月11日.
- Berberian, Sterling K. (1974). Lectures in Functional Analysis and Operator Theory. Graduate Texts in Mathematics. Vol. 15. New York: Springer. ISBN 978-0-387-90081-0. OCLC 878109401.
- Bourbaki, Nicolas (1987) [1981]. Topological Vector Spaces: Chapters 1–5. Éléments de mathématique. Translated by Eggleston, H.G.; Madan, S. Berlin New York: Springer-Verlag. ISBN 3-540-13627-4. OCLC 17499190.
- Conway, John (1990). A course in functional analysis. Graduate Texts in Mathematics. Vol. 96 (2nd ed.). New York: Springer-Verlag. ISBN 978-0-387-97245-9. OCLC 21195908.
- Dieudonné, Jean (1970). Treatise on Analysis, Volume II. Academic Press.
- Edwards, Robert E. (1995). Functional Analysis: Theory and Applications. New York: Dover Publications. ISBN 978-0-486-68143-6. OCLC 30593138.
- Grothendieck, Alexander (1973). Topological Vector Spaces . Translated by Chaljub, Orlando. New York: Gordon and Breach Science Publishers. ISBN 978-0-677-30020-7. OCLC 886098.
- Jarchow, Hans (1981). Locally convex spaces. Stuttgart: B.G. Teubner. ISBN 978-3-519-02224-4. OCLC 8210342.
- Köthe, Gottfried (1983) [1969]. Topological Vector Spaces I. Grundlehren der mathematischen Wissenschaften. Vol. 159. Translated by Garling, D.J.H. New York: Springer Science & Business Media. ISBN 978-3-642-64988-2. MR 0248498. OCLC 840293704.
- Narici, Lawrence; Beckenstein, Edward (2011). Topological Vector Spaces. Pure and applied mathematics (Second ed.). Boca Raton, FL: CRC Press. ISBN 978-1584888666. OCLC 144216834.
- Robertson, Alex P.; Robertson, Wendy J. (1980). Topological Vector Spaces. Cambridge Tracts in Mathematics. Vol. 53. Cambridge England: Cambridge University Press. ISBN 978-0-521-29882-7. OCLC 589250.
- Rudin, Walter (1973). Functional Analysis . International Series in Pure and Applied Mathematics. Vol. 25 (First ed.). New York, NY: McGraw-Hill Science/Engineering/Math. ISBN 9780070542259.
- Rudin, Walter (1991). Functional Analysis. International Series in Pure and Applied Mathematics. Vol. 8 (Second ed.). New York, NY: McGraw-Hill Science/Engineering/Math. ISBN 978-0-07-054236-5. OCLC 21163277.
- Schaefer, Helmut H.; Wolff, Manfred P. (1999). Topological Vector Spaces. GTM. Vol. 8 (Second ed.). New York, NY: Springer New York Imprint Springer. ISBN 978-1-4612-7155-0. OCLC 840278135.
- Swartz, Charles (1992). An introduction to Functional Analysis. New York: M. Dekker. ISBN 978-0-8247-8643-4. OCLC 24909067.
- Trèves, François (2006) [1967]. Topological Vector Spaces, Distributions and Kernels. Mineola, N.Y.: Dover Publications. ISBN 978-0-486-45352-1. OCLC 853623322.
- Vogt, Dietmar (2000). "Lectures on Fréchet spaces" (PDF). Bergische Universität Wuppertal.
- Wilansky, Albert (2013). Modern Methods in Topological Vector Spaces. Mineola, New York: Dover Publications, Inc. ISBN 978-0-486-49353-4. OCLC 849801114.
This article incorporates material from Proof of open mapping theorem on PlanetMath, which is licensed under the Creative Commons Attribution/Share-Alike License.
Further reading
[edit ]- "When is a complex of Banach spaces exact as condensed abelian groups?". MathOverflow. February 6, 2021.