Re: Les arguments

http://crasseux.com/books/ctutorial/argc-and-argv.html

argv[0] représente la chaine utilisée pour appeler le programme et non le programma appelant.

As you can see, the first argument (argv[0]) is the name by which the program was called, in this case gcc. Thus, there will always be at least one argument to a program, and argc will always be at least 1.
The following program accepts any number of command-line arguments and prints them out:
#include <stdio.h>
int main (int argc, char *argv[])
{
 int count;
 printf ("This program was called with \"%s\".\n",argv[0]);
 if (argc > 1)
 {
 for (count = 1; count < argc; count++)
 {
 printf("argv[%d] = %s\n", count, argv[count]);
 }
 }
 else
 {
 printf("The command had no other arguments.\n");
 }
 return 0;
}
If you name your executable fubar, and call it with the command ./fubar a b c, it will print out the following text:
This program was called with "./fubar".
argv[1] = a
argv[2] = b
argv[3] = c