Forum Programmation.shell combine grep and sed in one command

I need to get all log done in my project. I'm using this command to do that:

grep -rnw 1ドル -e "Logger.[view]*;$" >> log.txt

this line return all lines containing Logger.[one of the these caracters] contained in the project directory "1ドル" except that there are some lines written on 2 or 3 lines (IDE formating). In this case I get only the first line only. I want to get the complete text of that log knowing that a log line will always end with " );" example of such line :

 Logger.v(xxxxxxxxxxxxx
 xxxxxxxxxxxxxxxx);

Here is my script:

 #!/bin/bash 
 echo "Hello Logger!
 # get project path 
 echo "project directory is 1ドル"
 # get all project logs and store them into temporary file tmp.txt for processing
 grep -rnw 1ドル -e "Logger.[view]" >> tmp.txt
 echo "tmp.txt created successfully"
 # remove package name from previous result and store result into log.txt
 sed -r 's/.{52}//' tmp.txt >> log.txt
 echo "log.txt created successfully"
grep command return **file_path/file_name : line_number : line**. I found this command that returns only the line even if it is written in 2 or 3 lines but without the **file_path** **file_name** and the **line_number**
 sed -n '/Logger.[viewd]/{:start /;/!{N;b start};/Logger.[viewd]/p}' Main.java

Is there a way to have those two results combined. example :

 /home/xxx/xxx/xxx/Main.java:97:Logger.i(xxxxxxxxxxxxx); 
 /home/xxx/xxx/xxx/Main.java:106:Logger.d(yyyyyyyyyyyy
 yyyyyyyyyyyyyyyyyyyy);