This page shows how to construct a
right triangle that has the hypotenuse (H) and one angle (A) given.
It works in three steps:
Argument
Reason
We first prove that ∆BCA is a right triangle
2
Therefore ∆BCA is a right triangle
By definition of a right triangle, one angle must be 90°
Now prove BA is the hypotenuse H
3
AB = the given hypotenuse H
AB was copied from H at the same compass width
Now prove ∠BAC is the given angle A
4
m∠BAC = given m∠A
Copied using the procedure in
Copying an angle.
See that page for proof
9
∆BCA is a right triangle with the desired hypotenuse H and angle A
From (2), (3), (4)
-
Q.E.D
containing two HA triangle construction problems.
When you get to the page, use the browser print command to print as many as you wish. The printed output is not copyright.
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