Direct comparison test
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In mathematics, the comparison test, sometimes called the direct comparison test to distinguish it from similar related tests (especially the limit comparison test), provides a way of deducing whether an infinite series or an improper integral converges or diverges by comparing the series or integral to one whose convergence properties are known.
For series
[edit ]In calculus, the comparison test for series typically consists of a pair of statements about infinite series with non-negative (real-valued) terms:[1]
- If the infinite series {\displaystyle \sum b_{n}} converges and {\displaystyle 0\leq a_{n}\leq b_{n}} for all sufficiently large n (that is, for all {\displaystyle n>N} for some fixed value N), then the infinite series {\displaystyle \sum a_{n}} also converges.
- If the infinite series {\displaystyle \sum b_{n}} diverges and {\displaystyle 0\leq b_{n}\leq a_{n}} for all sufficiently large n, then the infinite series {\displaystyle \sum a_{n}} also diverges.
Note that the series having larger terms is sometimes said to dominate (or eventually dominate) the series with smaller terms.[2]
Alternatively, the test may be stated in terms of absolute convergence, in which case it also applies to series with complex terms:[3]
- If the infinite series {\displaystyle \sum b_{n}} is absolutely convergent and {\displaystyle |a_{n}|\leq |b_{n}|} for all sufficiently large n, then the infinite series {\displaystyle \sum a_{n}} is also absolutely convergent.
- If the infinite series {\displaystyle \sum b_{n}} is not absolutely convergent and {\displaystyle |b_{n}|\leq |a_{n}|} for all sufficiently large n, then the infinite series {\displaystyle \sum a_{n}} is also not absolutely convergent.
Note that in this last statement, the series {\displaystyle \sum a_{n}} could still be conditionally convergent; for real-valued series, this could happen if the an are not all nonnegative.
The second pair of statements are equivalent to the first in the case of real-valued series because {\displaystyle \sum c_{n}} converges absolutely if and only if {\displaystyle \sum |c_{n}|}, a series with nonnegative terms, converges.
Proof
[edit ]The proofs of all the statements given above are similar. Here is a proof of the third statement.
Let {\displaystyle \sum a_{n}} and {\displaystyle \sum b_{n}} be infinite series such that {\displaystyle \sum b_{n}} converges absolutely (thus {\displaystyle \sum |b_{n}|} converges), and without loss of generality assume that {\displaystyle |a_{n}|\leq |b_{n}|} for all positive integers n. Consider the partial sums
- {\displaystyle S_{n}=|a_{1}|+|a_{2}|+\ldots +|a_{n}|,\ T_{n}=|b_{1}|+|b_{2}|+\ldots +|b_{n}|.}
Since {\displaystyle \sum b_{n}} converges absolutely, {\displaystyle \lim _{n\to \infty }T_{n}=T} for some real number T. For all n,
- {\displaystyle 0\leq S_{n}=|a_{1}|+|a_{2}|+\ldots +|a_{n}|\leq |a_{1}|+\ldots +|a_{n}|+|b_{n+1}|+\ldots =S_{n}+(T-T_{n})\leq T.}
{\displaystyle S_{n}} is a nondecreasing sequence and {\displaystyle S_{n}+(T-T_{n})} is nonincreasing. Given {\displaystyle m,n>N} then both {\displaystyle S_{n},S_{m}} belong to the interval {\displaystyle [S_{N},S_{N}+(T-T_{N})]}, whose length {\displaystyle T-T_{N}} decreases to zero as {\displaystyle N} goes to infinity. This shows that {\displaystyle (S_{n})_{n=1,2,\ldots }} is a Cauchy sequence, and so must converge to a limit. Therefore, {\displaystyle \sum a_{n}} is absolutely convergent.
For integrals
[edit ]The comparison test for integrals may be stated as follows, assuming continuous real-valued functions f and g on {\displaystyle [a,b)} with b either {\displaystyle +\infty } or a real number at which f and g each have a vertical asymptote:[4]
- If the improper integral {\displaystyle \int _{a}^{b}g(x),円dx} converges and {\displaystyle 0\leq f(x)\leq g(x)} for {\displaystyle a\leq x<b}, then the improper integral {\displaystyle \int _{a}^{b}f(x),円dx} also converges with {\displaystyle \int _{a}^{b}f(x),円dx\leq \int _{a}^{b}g(x),円dx.}
- If the improper integral {\displaystyle \int _{a}^{b}g(x),円dx} diverges and {\displaystyle 0\leq g(x)\leq f(x)} for {\displaystyle a\leq x<b}, then the improper integral {\displaystyle \int _{a}^{b}f(x),円dx} also diverges.
Ratio comparison test
[edit ]Another test for convergence of real-valued series, similar to both the direct comparison test above and the ratio test, is called the ratio comparison test:[5]
- If the infinite series {\displaystyle \sum b_{n}} converges and {\displaystyle a_{n}>0}, {\displaystyle b_{n}>0}, and {\displaystyle {\frac {a_{n+1}}{a_{n}}}\leq {\frac {b_{n+1}}{b_{n}}}} for all sufficiently large n, then the infinite series {\displaystyle \sum a_{n}} also converges.
- If the infinite series {\displaystyle \sum b_{n}} diverges and {\displaystyle a_{n}>0}, {\displaystyle b_{n}>0}, and {\displaystyle {\frac {a_{n+1}}{a_{n}}}\geq {\frac {b_{n+1}}{b_{n}}}} for all sufficiently large n, then the infinite series {\displaystyle \sum a_{n}} also diverges.
See also
[edit ]- Convergence tests
- Convergence (mathematics)
- Dominated convergence theorem
- Integral test for convergence
- Limit comparison test
- Monotone convergence theorem
Notes
[edit ]References
[edit ]- Ayres, Frank Jr.; Mendelson, Elliott (1999). Schaum's Outline of Calculus (4th ed.). New York: McGraw-Hill. ISBN 0-07-041973-6.
- Buck, R. Creighton (1965). Advanced Calculus (2nd ed.). New York: McGraw-Hill.
- Knopp, Konrad (1956). Infinite Sequences and Series. New York: Dover Publications. § 3.1. ISBN 0-486-60153-6.
{{cite book}}
: ISBN / Date incompatibility (help) - Munem, M. A.; Foulis, D. J. (1984). Calculus with Analytic Geometry (2nd ed.). Worth Publishers. ISBN 0-87901-236-6.
- Silverman, Herb (1975). Complex Variables. Houghton Mifflin Company. ISBN 0-395-18582-3.
- Whittaker, E. T.; Watson, G. N. (1963). A Course in Modern Analysis (4th ed.). Cambridge University Press. § 2.34. ISBN 0-521-58807-3.
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: ISBN / Date incompatibility (help)