std::inplace_vector<T,N>::pop_back
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Tables
std::inplace_vector
inplace_vector::pop_back
constexpr void pop_back();
Removes the last element of the container.
If empty() is true:
- If the implementation is hardened, a contract violation occurs. Moreover, if the contract-violation handler returns under "observe" evaluation semantic, the behavior is undefined.
- If the implementation is not hardened, the behavior is undefined.
Iterators and references to the last element are invalidated. The end() iterator is also invalidated.
[edit] Complexity
Constant.
[edit] Example
Run this code
#include <inplace_vector> #include <print> int main() { std::inplace_vector <int, 4> numbers{1, 2, 3}; for (; not numbers.empty(); numbers.pop_back()) std::println ("{}", numbers); }
Output:
[1, 2, 3] [1, 2] [1]