std::inplace_vector<T,N>::push_back
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std::inplace_vector 
 
 
 
inplace_vector::push_back
constexpr reference push_back( const T& value );
 (1) 
 (since C++26) 
constexpr reference push_back( T&& value );
 (2) 
 (since C++26) 
Appends the given element value to the end of the container.
1) The new element is initialized as a copy of value.
2) value is moved into the new element.
No iterators or references are invalidated, except end(), which is invalidated if the insertion occurs.
[edit] Parameters
 value
 -
 the value of the element to append
 Type requirements
 -
T must meet the requirements of CopyInsertable in order to use overload (1).
 -
T must meet the requirements of MoveInsertable in order to use overload (2).
[edit] Return value
back(), i.e. a reference to the inserted element.
[edit] Complexity
Constant.
[edit] Exceptions
- std::bad_alloc if size() == capacity() before invocation.
- Any exception thrown by initialization of inserted element.
If an exception is thrown for any reason, these functions have no effect (strong exception safety guarantee).
[edit] Example
Run this code
#include <inplace_vector> #include <new> #include <print> #include <string> int main() { std::inplace_vector <std::string, 2> fauna; std::string dog{"\N{DOG}"}; fauna.push_back("\N{CAT}"); // overload (1) fauna.push_back(std::move(dog)); // overload (2) std::println ("fauna = {}", fauna); try { fauna.push_back("\N{BUG}"); // throws: there is no space } catch(const std::bad_alloc & ex) { std::println ("{}", ex.what()); } std::println ("fauna = {}", fauna); }
Possible output:
fauna = ["🐈", "🐕"] std::bad_alloc fauna = ["🐈", "🐕"]