In Matlab script, how would you compute a Reimann sum to approximate the area under the y=sin(x) from a =0 to b = p1/2 with n=6 subintervals using left-endpoints. Use for loop. Assign the result to Lsum.

please solve using the first step i did which was c(n,n) = 1/C(5,5) = 1. <n=5> P(n,n) = n!/p(8,8)= 8! <n=8>

Consider a list of n unique ordered integers, where you are allowed to remove m of them. The goal is to maximize the distance between the remaining closest numbers. As an example, consider the list [1, 4, 5, 6, 8, 9], where we are allowed to remove two numbers. Here, an optimal solution would be to remove the numbers 5 and 8, leaving us with the list [1,4,6,9]. The distance between the closest remaining numbers is 2 (between 4 and 6). The proposed greedy algorithm to this problem is to take a pair of numbers which are currently closest together and remove the one which would result in the better solution. Using [1, 4, 5, 6, 8, 9] again as an example, the greedy algorithm would look at one of the closest pairs of numbers (4,5), (5,6) or (8,9). Without loss if generality assume it examines the pair (4,5), 5 is closer to 6 than 4 is to 1, so the algorithm would choose to remove 5, leaving the list [1,4,6,8,9]. The algorithm would then look again at a closest pair of numbers, (8,9) and...

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