JS How to remove object in multi demension array?

Question

I have array like this

let quotes = [
 {
 quoteNumber :'001',
 items : [
 {
 partnumber : '5551',
 supplierQty : 0,
 stock : 5
 },
 {
 partnumber : '5552',
 supplierQty : 1,
 stock : 0
 },
 {
 partnumber : '5553',
 supplierQty : 0,
 stock : 2
 }
 ]
 },
 {
 quoteNumber : '002',
 items : [
 {
 partnumber : '5554',
 supplierQty : 1,
 stock : 0
 },
 {
 partnumber : '5552',
 supplierQty : 5,
 stock : 0
 },
 {
 partnumber : '5553',
 supplierQty : 0,
 stock : 2
 }
 ]
 },
 {
 quoteNumber : '003',
 items : [
 {
 partnumber : '5554',
 supplierQty : 0,
 stock : 1
 },
 {
 partnumber : '5552',
 supplierQty : 0,
 stock : 3
 },
 {
 partnumber : '5553',
 supplierQty : 0,
 stock : 2
 }
 ]
 }
]

the result that I want is remove items inside quote that has supplierQty === 0 and remove quote that every items in it has supplierQty === 0

this is the result that I want.

let quotes = [
 {
 quoteNumber :'001',
 items : [
 
 {
 partnumber : '5552',
 supplierQty : 1,
 stock : 0
 }
 ]
 },
 {
 quoteNumber : '002',
 items : [
 {
 partnumber : '5554',
 supplierQty : 1,
 stock : 0
 },
 {
 partnumber : '5552',
 supplierQty : 5,
 stock : 0
 }
 ]
 }
]

this is my code

let results = quotes.filter((quote , index) => {
 
 let filterQuote = quote.items.filter((item) => {
 return item.supplierQty > 0; 
 })
 
 return filterQuote.length > 0;
 
})
 
console.log(results);

but It just remove quote 003 only . It didn't remove items inside quote 001 and 002 .

How can I do that . thank for help

results = [
 {
 quoteNumber :'001',
 items : [
 {
 partnumber : '5551',
 supplierQty : 0,
 stock : 5
 },
 {
 partnumber : '5552',
 supplierQty : 1,
 stock : 0
 },
 {
 partnumber : '5553',
 supplierQty : 0,
 stock : 2
 }
 ]
 },
 {
 quoteNumber : '002',
 items : [
 {
 partnumber : '5554',
 supplierQty : 1,
 stock : 0
 },
 {
 partnumber : '5552',
 supplierQty : 5,
 stock : 0
 },
 {
 partnumber : '5553',
 supplierQty : 0,
 stock : 2
 }
 ]
 }
]

Answer 1

You need to filter items first and remove the quote which does not contain any item using Array.filter.

const quotes = [
 {
 quoteNumber :'001',
 items : [
 {
 partnumber : '5551',
 supplierQty : 0,
 stock : 5
 },
 {
 partnumber : '5552',
 supplierQty : 1,
 stock : 0
 },
 {
 partnumber : '5553',
 supplierQty : 0,
 stock : 2
 }
 ]
 },
 {
 quoteNumber : '002',
 items : [
 {
 partnumber : '5554',
 supplierQty : 1,
 stock : 0
 },
 {
 partnumber : '5552',
 supplierQty : 5,
 stock : 0
 },
 {
 partnumber : '5553',
 supplierQty : 0,
 stock : 2
 }
 ]
 },
 {
 quoteNumber : '003',
 items : [
 {
 partnumber : '5554',
 supplierQty : 0,
 stock : 1
 },
 {
 partnumber : '5552',
 supplierQty : 0,
 stock : 3
 },
 {
 partnumber : '5553',
 supplierQty : 0,
 stock : 2
 }
 ]
 }
];
const results = quotes.map(({ items, ...quote }) => ({
 ...quote,
 items: items.filter(({ supplierQty }) => supplierQty > 0)
})).filter(({ items }) => items.length > 0);
console.log(results);

Answer 2

You need to reduce the array and filter only the inner part and add a new array if the length of the inner filtering is greater than zero.

let quotes = [{ quoteNumber: '001', items: [{ partnumber: '5551', supplierQty: 0, stock: 5 }, { partnumber: '5552', supplierQty: 1, stock: 0 }, { partnumber: '5553', supplierQty: 0, stock: 2 }] }, { quoteNumber: '002', items: [{ partnumber: '5554', supplierQty: 1, stock: 0 }, { partnumber: '5552', supplierQty: 5, stock: 0 }, { partnumber: '5553', supplierQty: 0, stock: 2 }] }, { quoteNumber: '003', items: [{ partnumber: '5554', supplierQty: 0, stock: 1 }, { partnumber: '5552', supplierQty: 0, stock: 3 }, { partnumber: '5553', supplierQty: 0, stock: 2 }] }],
 result = quotes.reduce((r, { items, ...o }) => {
 items = items.filter(({ supplierQty }) => supplierQty);
 if (items.length) r.push({ ...o, items });
 return r;
 }, []);
console.log(result);

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