Deleting specific array element from multidimensional array?

Question

I'm having trouble cycling through a multidimensional array and deleting a specific element array. My multidimensional array looks a little like this:

myArray = [["Tom", "161"], ["Dick", "29"], ["Harry", "46"]];

So if I have the number 29. What's the most efficient way to cycle through this array and delete the array element who's second element is 29? i.e. ["Dick", "29"]

• Felix Kling: A for loop. Depending on what else you are doing with the data, you could sort the array first.
• aadu: I thought it would be some combination of indexOf and splice?
• Felix Kling: indexOf won't really work, since you are looking for an element inside the elements. But you can easily test what is faster with jsperf.com.
• aadu: Yeah, that's what I thought which is why I was asking. But I'm not sure what the for loop should look like to achieve this?

Answer 1

var myArray = [["Tom", "161"], ["Dick", "29"], ["Harry", "46"]];
var myNewArray = myArray.filter(function(item){ return item[1] != 29 }) 

.filter uses native code to loop over your array. Building a new array could of course be more expensive than just cutting a part out of the old one, to be tested.

• aadu: That works, but you think making a new array is less efficient than the above loop and splice method?
• brbcoding: This method is substanially faster than mine... jsperf.com/removearrfrommulti

Answer 2

myArray = [["Tom", "161"], ["Dick", "29"], ["Harry", "46"]];
for(var i = 0; i <= myArray.length - 1; i++){
 if(myArray[i][1] == "29"){
 myArray[i].splice(0,2);
 }
}
console.log(myArray);
// returns [ [ 'Tom', '161' ], [], [ 'Harry', '46' ] ]

Answer 3

const organizers = [
 {
 id: '83f58b20-011d-11ed-b71c-47e6c5dfe098',
 createdAt: '2022-07-11T13:29:39.794Z',
 updatedAt: '2022-07-11T13:29:39.794Z',
 organizerId: '83deced0-011d-11ed-b71c-47e6c5dfe098',
 tournamentId: '83b37910-011d-11ed-b71c-47e6c5dfe098',
 organizerName: null
 },
 {
 id: '83f58b21-011d-11ed-b71c-47e6c5dfe098',
 createdAt: '2022-07-11T13:29:39.794Z',
 updatedAt: '2022-07-11T13:29:39.794Z',
 organizerId: '83e18df0-011d-11ed-b71c-47e6c5dfe098',
 tournamentId: '83b37910-011d-11ed-b71c-47e6c5dfe098',
 organizerName: 'MANOJ ABCD'
 }
];
const removeorganizerId = "83e18df0-011d-11ed-b71c-47e6c5dfe098"
var myNewArray = organizers.filter(function(item){ return item.organizerId !== removeorganizerId });
console.log("myNewArray ===> ", myNewArray);

Check Demo Here

https://onecompiler.com/javascript/3y9unh6vt

Answer 4

The answer by brbcoding deletes the content of the array element but does not delete it. Here is a way around that:

myArray = [["Tom", "161"], ["Dick", "29"], ["Harry", "46"]];
document.getElementById("a").innerHTML = myArray;
for(var i = 0; i <= myArray.length - 1; i++){
 if(myArray[i][1] == "29"){
 myArray.splice(i--,1);
}
}
document.getElementById("b").innerHTML = myArray;
console.log(myArray);

https://jsfiddle.net/tmzshopping/dfdveazk/

The splice removes one row (the 1 in the argument), you can remove 2 rows by replacing the 1 by 2. i-- reduces the length of the array.

Answer 5

 array_name = [[1,2,3],[],['Hi','hello','world']] 
 let temp = []
 array_name.forEach(element => {
 if (element != '' || `enter condition here`) {
 temp.push(element)
 }
 });
 
 array_name = temp; // array_name = [ [1,2,3], ['Hi','hello','world'] ]