Python Parameter Passing

Question

I'm working on making a modified version of pong for my college class and am having some trouble passing some methods. I believe I have everything set up the way it needs to to be able to do some parameter passing. The code runs fine and stops working just after the while loop in my main function. Any help is appreciated.

 import pygame
 SCR_WID, SCR_HEI = 640, 480
 class Player():
 def __init__(self):
 self.x, self.y = 16, SCR_HEI/2
 self.x1, self.y1 = SCR_WID-16, SCR_HEI/2
 self.speed = 3
 self.padWid, self.padHei = 8, 64
 self.score = 0
 self.scoreFont = pygame.font.Font("imagine_font.ttf", 64)
 def scoring(self):
 scoreBlit = self.scoreFont.render(str(self.score), 1, (0,0,0))
 screen.blit(scoreBlit, (32, 16))
 if self.score == 10:
 print ("player 1 wins!")
 exit()
 def scoring1(self):
 scoreBlit = self.scoreFont.render(str(self.score), 1, (0,0,0))
 screen.blit(scoreBlit, (SCR_HEI+92, 16))
 if self.score == 10:
 print ("Player 2 wins!")
 exit()
 def movement(self): 
 keys = pygame.key.get_pressed()
 if keys[pygame.K_w]:
 self.y -= self.speed
 elif keys[pygame.K_s]:
 self.y += self.speed
 if self.y <= 0:
 self.y = 0
 elif self.y >= SCR_HEI-64:
 self.y = SCR_HEI-64
 keys1 = pygame.key.get_pressed()
 if keys1[pygame.K_UP]:
 self.y1 -= self.speed
 elif keys1[pygame.K_DOWN]:
 self.y1 += self.speed
 if self.y1 <= 0:
 self.y1 = 0
 elif self.y >= SCR_HEI-64:
 self.y1 = SCR_HEI-64
 def draw(self):
 pygame.draw.rect(screen, (0,0,0), (self.x, self.y, self.padWid, self.padHei))
 pygame.draw.rect(screen, (0,0,0), (self.x1, self.y1, self.padWid, self.padHei))
 class Ball():
 def __init__(self):
 self.x, self.y = SCR_WID/2, SCR_HEI/2
 self.x1, self.y1 = SCR_WID/2, SCR_HEI/2
 self.speed_x = -3
 self.speed_y = 3
 self.size = 8
 def movement(self):
 self.x += self.speed_x
 self.y += self.speed_y
 if self.y <= 0:
 self.speed_y *= -1
 elif self.y >= SCR_HEI-self.size:
 self.speed_y *= -1
 if self.x <= 0:
 self.__init__()
 enemy.score += 1
 elif self.x >= SCR_WID-self.size:
 self.__init__()
 self.speed_x = 3
 player.score += 1
 for n in range(-self.size, player.padHei):
 if self.y == player.y + n:
 if self.x <= player.x + player.padWid:
 self.speed_x *= -1
 break
 n += 1
 self.x1 += self.speed_x
 self.y1 += self.speed_y
 if self.y1 <= 0:
 self.speed_y *= -1
 elif self.y1 >= SCR_HEI-self.size:
 self.speed_y *= -1
 if self.x1 <= 0:
 self.__init__()
 enemy.score += 1
 elif self.x1 >= SCR_WID-self.size:
 self.__init__()
 self.speed_x = 3
 player.score += 1
 for n in range(-self.size, enemy.padHei):
 if self.y1 == enemy.y1 + n:
 if self.x1 >= enemy.x1 - enemy.padWid:
 self.speed_x *= -1
 break
 n += 1
 def draw(self):
 pygame.draw.rect(screen, (112,138,144), (self.x, self.y, 8, 8))
 SCR_WID, SCR_HEI = 640, 480
 screen = pygame.display.set_mode((SCR_WID, SCR_HEI))
 pygame.display.set_caption("Justin's pong")
 pygame.font.init()
 clock = pygame.time.Clock()
 FPS = 60
 player = Player() 
 ball = Ball()
 enemy = Player()
 def main():
 while True:
 for event in pygame.event.get():
 if event.type == pygame.QUIT:
 print ("Game exited by user")
 exit()
 backgroundimage = pygame.image.load("background.png")
 ball.movement()
 player.movement()
 enemy.movement()
 position = (0,0)
 screen.fill((0, 0, 0))
 screen.blit(backgroundimage, position)
 ball.draw()
 player.draw()
 player.scoring()
 enemy.draw()
 enemy.scoring1()
 pygame.display.flip()
 clock.tick(FPS)
 main()

• MattDMo: Dude - indentation! Use 4 spaces, no more, no less.

Answer 1

Nothing beyond your while loop will be executed until the loop as been completed.

i = 0
while i < 5:
 print(i)
 i += 1
print('Finished!')

Output:

0
1
2
3
4
Finished!

• LinkBerest - SO sold our work: Also his for loop has a similar problem (not a breaking problem but not doing what he thinks it is either): n += 1 in a for with a range does not alter for n in range:
• Justin Farr: I understand what you're saying by saying that I need to complete the loop, I'm just not sure I understand how to do that. Wouldn't I have to do something with False to counteract the True or is that way off?
• Zach Gates: I'm not familiar with the pygame module, but it seems that the while loop isn't even needed. @JustinFarr
• LinkBerest - SO sold our work: @zachgates7 yes, with pygame you need a while True (to keep looping the game until it hits an end game situation). JustinFarr is just mistaken on a number of fundamental issues such as what should be wrapped in the while loop.