Replace pattern in Java

Question

I have the following text:

String text = "lorem ipsum @@MyText[1] lorem ipsum @@MyText[22]";

And I want to replace it by:

String text = "lorem ipsum /my/url/1 lorem ipsum /my/url/22;

I have done the following:

String newText = text.replaceAll("@@MyText\\[\\d*\\]", "/my/url/%s");

But in this way I get:

"lorem ipsum /my/url/%s lorem ipsum /my/url/%s;

How could I replace the given text but still conservating the number in the brackets?

Thank you very much in advance

• awksp: You could capture the number using parentheses and use that in the replacement, I think

Answer 1

You need to place number found in [...] in separate group and use match from that group in replacement via $id where id represents number of that group.

Use

replaceAll("@@MyText\\[(\\d+)\\]", "my/url/1ドル")
// ^^^^^^ group 1 ^^ part matched by group 1

• Genzotto: That's it! I did it in a more complex way: "(@@MyText\[)(\\d*)(\])", and then using 2,ドル but I prefer your solution. Thank you!