Java: Regex replacing

Question

I have this String:

foo bar 567 baz

Now I want to add before each number the String num:.
So the result has to be:

foo bar num:567 baz

Also this has to work:

foo 73761 barbazboom!! 87
result:
foo num:73761 barbazboom!! num:87

The regex to search number is this: [0-9]+
But I want to replace the matching substring with num: + [the matching substring]

I now wrote an example with numbers, but an other example can be: add before each e-mail-address Email found:

• lutz: Could you please post the code for the num:[0-9]+ case?
• Greg: What should happen to numbers within words - 123foo, foo123 or foo123foo? Then there's signed numbers (-123), formatted numbers (1,234) and decimals (1,234.567).
• Martijn Courteaux: @Greg: Just edit the regex, no?

Answer 1

Make use of grouping. You can use the parentheses ( and ) to define groups and identify the group in the result by $n where n is the group index.

String string = "foo bar 567 baz";
String replaced = string.replaceAll("(\\d+)", "num:1ドル");

Answer 2

"foo bar 567 baz".replaceAll("(\\d+)", "num:1ドル");