Parsing jsonarray in android

Question

i need to parse the json array contacts from the below json

{
 },
 //Truncated for clarity
 ]
}

• aroth: That's valid JSON according to jsonlint, what's the problem?
• Quintin Robinson: What is the issue you are having parsing this?
• harish: i need to parse the jsonarray contacts
• harish: i get all the datas when parsing but in contacts array i need to get the "t" and "w" separately
• harish: i used the getString() but when "t"is not "w" is getting as "t" data

Answer 1

Parsing is easy. First get json-simple and add it to your project (or you can use the built-in JSON library, if you like how everything in that library can throw a checked JSONException).

Next, your entire response-text is a valid JSON object. So do:

JSONObject response = (JSONObject)JSONValue.parse(responseText);

Your object has an array of results under the "result" key. You can get that like:

JSONArray results = (JSONArray)response.get("result");

Your array contains a set of objects that you want to iterate over to get the contact info for each one. For example:

for (Object obj : results) {
 JSONObject entry = (JSONObject)obj;
 JSONArray contacts = (JSONArray)entry.get("contact");
 for (Object contact : contacts) {
 System.out.println(contact);
 }
}

Note that whomever put that JSON together decided to use an array type for holding each individual contact entry. An object type would have made a lot more sense, but as-is, contact.get(0) will give you the type-code for the contact entry (t, w, etc.), and contact.get(1) will give you the actual contact number/address/whatever.

Answer 2

i think this isnt not a valid Json. normal Json must have a "Label" : "value". Label and value must be seperated by colon :

"w","www.firmdale.com"

Should be like this

"w":"www.firmdale.com"

http://code.google.com/p/jsonvalidator/

Edited: to be more clear and specific as per Aroth

object
 {}
 { members } 
members
 pair
 pair , members
pair
 string : value
array
 []
 [ elements ]
elements
 value
 value , elements
value
 string
 number
 object
 array
 true
 false
 null 

• aroth: It's valid JSON, but logically they should have used a JSON object instead of a JSON array for storing the individual contact entries.
• Mohammed Azharuddin Shaikh: You should format your output as valid JSON even if it's single string. stackoverflow.com/questions/5950297/… see link's comment specially.
• harish: ya read it... can i der be any solution or is it needed to change in webservice
• Mohammed Azharuddin Shaikh: and also refer sencha.com/forum/showthread.php?22990-Json-Invalid-label

Answer 3

 private JSONObject jObject;
 jObject = new JSONObject(your response as string);
 //this will give you json object for HotelInformationResponse
 JSONArray menuitemArray = popupObject.getJSONArray("result"); 
 // loop through this array to get all values 

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