parse json array in android

Question

I need a help... I have a php file which returns me two json Arrays which are as follows:

[{ "id":"1",
 "item":"hammers",
 "aisle":"20"
 }
 { "id":"1",
 "item":"hammers",
 "aisle":"20"
 }]
[{ "id":"1",
 "itemFound":"Your item #item",
 "ThankYou":"and Thank You for using Txtcore!"
 }]

Now, I want to get the second array items in Android. I have the following code now which is like : JSONArray jsonArray = new JSONArray(result);

 for (int i = 0; i < jsonArray.length(); i++) {
 JSONObject jsonObject = jsonArray.getJSONObject(i); 
 items.add(jsonObject.getString("item"));
 aisles.add(""+jsonObject.getString("item");
 }

But obviously, that returns me the objects from the first array. I want to get the Objects from the second array. Any suggestions.

• Spring Breaker: is it the full JSON data?
• user3485703: yes, the top coding is the json data sent by the php file.
• user3485703: I just want to get the second array object values in java/android.
• meda: is this really your JSON? it isnt valid
• Spring Breaker: @user3485703: I don't think it should be the complete json data.Do check it again.

Answer 1

Your JSON is not valid but u can get your element as follows. It is a solution from many(just a worlaround).

String str = "YOUR_JSON_RESPONSE";
String array[] = str.split("\\[\\{");// 
try {
 JSONArray jsonArray=new JSONArray("[{" + array[2]));
} catch (JSONException e) {
 // TODO Auto-generated catch block
 e.printStackTrace();
}

Answer 2

I guess you'll have to do some dirty coding because the data return by the PHP page is not well formed JSON. You could try to transform the JSON data to: { "data" : [ <array_1>, <array_2> ]} And then use the JSON parser. A simple replacement with a regexp could be fine.

 result.replaceAll("\\]\\s*\\[", "], [");
 StringBuffer buffer=new StringBuffer(result);
 buffer.insert(0,"{ \"data\": ");
 buffer.append(" }");
 JSONObject jsonObject = new JSONObject(buffer.toString());
 JSONArray secondArray= jsonObject.getJSONArray("data").getJSONArray(1);

The creation of a valid JSON string can be done in one step with the appropriate regexp. Hope some one with more time can post it here.