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javadev merged 2 commits into javadev:main from ThanhNIT:tasks-374-378-380
Dec 17, 2021
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View file Open in desktop
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package g0301_0400.s0374_guess_number_higher_or_lower;

// #Easy #Binary_Search #Interactive

/**
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Please not use javadoc comments.

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* Forward declaration of guess API.
*
* @param num your guess
* @return -1 if num is lower than the guess number 1 if num is higher than the guess number
* otherwise return 0 int guess(int num);
*/
public class Solution {
public int guessNumber(int n) {
int left = 1;
int right = n;
int mid;
while (left <= right) {
mid = left + (right - left) / 2;
if (guess(mid) == 1) {
left = mid + 1;
} else if (guess(mid) == -1) {
right = mid - 1;
} else {
return mid;
}
}
return -1;
}

// Assume we pick 7
private int guess(int num) {
return Integer.compare(7, num);
}
}
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374\. Guess Number Higher or Lower

Easy

We are playing the Guess Game. The game is as follows:

I pick a number from `1` to `n`. You have to guess which number I picked.

Every time you guess wrong, I will tell you whether the number I picked is higher or lower than your guess.

You call a pre-defined API `int guess(int num)`, which returns 3 possible results:

* `-1`: The number I picked is lower than your guess (i.e. `pick < num`).
* `1`: The number I picked is higher than your guess (i.e. `pick > num`).
* `0`: The number I picked is equal to your guess (i.e. `pick == num`).

Return _the number that I picked_.

**Example 1:**

**Input:** n = 10, pick = 6

**Output:** 6

**Example 2:**

**Input:** n = 1, pick = 1

**Output:** 1

**Example 3:**

**Input:** n = 2, pick = 1

**Output:** 1

**Example 4:**

**Input:** n = 2, pick = 2

**Output:** 2

**Constraints:**

* <code>1 <= n <= 2<sup>31</sup> - 1</code>
* `1 <= pick <= n`
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package g0301_0400.s0378_kth_smallest_element_in_a_sorted_matrix;

// #Medium #Top_Interview_Questions #Array #Sorting #Binary_Search #Matrix #Heap_Priority_Queue

public class Solution {
public int kthSmallest(int[][] matrix, int k) {
if (matrix == null || matrix.length == 0) {
return -1;
}
int start = matrix[0][0];
int end = matrix[matrix.length - 1][matrix[0].length - 1];
// O(log(max-min)) time
while (start + 1 < end) {
int mid = start + (end - start) / 2;
if (countLessEqual(matrix, mid) < k) {
// look towards end
start = mid;
} else {
// look towards start
end = mid;
}
}

// leave only with start and end, one of them must be the answer
// try to see if start fits the criteria first
if (countLessEqual(matrix, start) >= k) {
return start;
} else {
return end;
}
}

// countLessEqual
// O(n) Time
private int countLessEqual(int[][] matrix, int target) {
// binary elimination from top right
int row = 0;
int col = matrix[0].length - 1;
int count = 0;
while (row < matrix.length && col >= 0) {
if (matrix[row][col] == target) {
// get the count in current row
count += col + 1;
row++;
} else if (matrix[row][col] > target) {
// eliminate the current col
col--;
} else {
// get the count in current row
count += col + 1;
row++;
}
}
return count;
}
}
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378\. Kth Smallest Element in a Sorted Matrix

Medium

Given an `n x n` `matrix` where each of the rows and columns is sorted in ascending order, return _the_ <code>k<sup>th</sup></code> _smallest element in the matrix_.

Note that it is the <code>k<sup>th</sup></code> smallest element **in the sorted order**, not the <code>k<sup>th</sup></code> **distinct** element.

You must find a solution with a memory complexity better than <code>O(n<sup>2</sup>)</code>.

**Example 1:**

**Input:** matrix = \[\[1,5,9\],\[10,11,13\],\[12,13,15\]\], k = 8

**Output:** 13

**Explanation:** The elements in the matrix are \[1,5,9,10,11,12,13,**13**,15\], and the 8<sup>th</sup> smallest number is 13

**Example 2:**

**Input:** matrix = \[\[-5\]\], k = 1

**Output:** -5

**Constraints:**

* `n == matrix.length == matrix[i].length`
* `1 <= n <= 300`
* <code>-10<sup>9</sup> <= matrix[i][j] <= 10<sup>9</sup></code>
* All the rows and columns of `matrix` are **guaranteed** to be sorted in **non-decreasing order**.
* <code>1 <= k <= n<sup>2</sup></code>

**Follow up:**

* Could you solve the problem with a constant memory (i.e., `O(1)` memory complexity)?
* Could you solve the problem in `O(n)` time complexity? The solution may be too advanced for an interview but you may find reading [this paper](http://www.cse.yorku.ca/~andy/pubs/X+Y.pdf) fun.
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package g0301_0400.s0380_insert_delete_getrandom_o1;

import java.util.*;

class RandomizedSet {
private final Random rand;
private final List<Integer> list;
private final Map<Integer, Integer> map;

/** Initialize your data structure here. */
public RandomizedSet() {
this.rand = new Random();
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this.list = new ArrayList<>();
this.map = new HashMap<>();
}

/**
* Inserts a value to the set. Returns true if the set did not already contain the specified
* element.
*/
public boolean insert(int val) {
if (this.map.containsKey(val)) {
return false;
}
this.list.add(val);
this.map.put(val, list.size() - 1);
return true;
}

/** Removes a value from the set. Returns true if the set contained the specified element. */
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It may be a simple comment, not javadoc.

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public boolean remove(int val) {
if (!this.map.containsKey(val)) {
return false;
}
int index = this.map.get(val);
if (index == this.list.size() - 1) {
this.list.remove(index);
this.map.remove(val);
return true;
}
int value = list.get(list.size() - 1);
this.list.set(index, value);
this.list.remove(this.list.size() - 1);
this.map.remove(val);
this.map.put(value, index);
return true;
}

/** Get a random element from the set. */
public int getRandom() {
return this.list.get(rand.nextInt(list.size()));
}
}

/**
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Please not use javadoc comments to avoid reformatting block.

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* Your RandomizedSet object will be instantiated and called as such: RandomizedSet obj = new
* RandomizedSet(); boolean param_1 = obj.insert(val); boolean param_2 = obj.remove(val); int
* param_3 = obj.getRandom();
*/
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380\. Insert Delete GetRandom O(1)

Medium

Implement the `RandomizedSet` class:

* `RandomizedSet()` Initializes the `RandomizedSet` object.
* `bool insert(int val)` Inserts an item `val` into the set if not present. Returns `true` if the item was not present, `false` otherwise.
* `bool remove(int val)` Removes an item `val` from the set if present. Returns `true` if the item was present, `false` otherwise.
* `int getRandom()` Returns a random element from the current set of elements (it's guaranteed that at least one element exists when this method is called). Each element must have the **same probability** of being returned.

You must implement the functions of the class such that each function works in **average** `O(1)` time complexity.

**Example 1:**

**Input** \["RandomizedSet", "insert", "remove", "insert", "getRandom", "remove", "insert", "getRandom"\] \[\[\], \[1\], \[2\], \[2\], \[\], \[1\], \[2\], \[\]\]
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It looks like multiline block.

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**Output:** \[null, true, false, true, 2, true, false, 2\]

**Explanation:**

RandomizedSet randomizedSet = new RandomizedSet();
randomizedSet.insert(1); // Inserts 1 to the set. Returns true as 1 was inserted successfully.
randomizedSet.remove(2); // Returns false as 2 does not exist in the set.
randomizedSet.insert(2); // Inserts 2 to the set, returns true. Set now contains \[1,2\].
randomizedSet.getRandom(); // getRandom() should return either 1 or 2 randomly.
randomizedSet.remove(1); // Removes 1 from the set, returns true. Set now contains \[2\].
randomizedSet.insert(2); // 2 was already in the set, so return false.
randomizedSet.getRandom(); // Since 2 is the only number in the set, getRandom() will always return 2.

**Constraints:**

* <code>-2<sup>31</sup> <= val <= 2<sup>31</sup> - 1</code>
* At most `2 * `<code>10<sup>5</sup></code> calls will be made to `insert`, `remove`, and `getRandom`.
* There will be **at least one** element in the data structure when `getRandom` is called.
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package g0301_0400.s0374_guess_number_higher_or_lower;

import static org.hamcrest.CoreMatchers.equalTo;
import static org.hamcrest.MatcherAssert.assertThat;

import org.junit.jupiter.api.Test;

class SolutionTest {
@Test
void guessNumber() {
assertThat(new Solution().guessNumber(10), equalTo(7));
}

@Test
void guessNumber2() {
assertThat(new Solution().guessNumber(1), equalTo(-1));
}

@Test
void guessNumber3() {
assertThat(new Solution().guessNumber(2), equalTo(-1));
}

@Test
void guessNumber4() {
assertThat(new Solution().guessNumber(6), equalTo(-1));
}
}
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package g0301_0400.s0378_kth_smallest_element_in_a_sorted_matrix;

import static org.hamcrest.CoreMatchers.equalTo;
import static org.hamcrest.MatcherAssert.assertThat;

import org.junit.jupiter.api.Test;

class SolutionTest {
@Test
void kthSmallest() {
assertThat(
new Solution().kthSmallest(new int[][] {{1, 5, 9}, {10, 11, 13}, {12, 13, 15}}, 8),
equalTo(13));
}

@Test
void kthSmallest2() {
assertThat(new Solution().kthSmallest(new int[][] {{-5}}, 1), equalTo(-5));
}
}
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package g0301_0400.s0380_insert_delete_getrandom_o1;

import static org.hamcrest.CoreMatchers.equalTo;
import static org.hamcrest.MatcherAssert.assertThat;

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
import org.junit.jupiter.api.Test;

class RandomizedSetTest {
@Test
void RandomizedSet() {
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Please name method from non capital letter.

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List<String> result = new ArrayList<>();
RandomizedSet randomizedSet = null;
result.add(randomizedSet + "");
randomizedSet = new RandomizedSet();
result.add(randomizedSet.insert(1) + "");
result.add(randomizedSet.remove(2) + "");
result.add(randomizedSet.insert(2) + "");
int random = randomizedSet.getRandom();
result.add(random + "");
result.add(randomizedSet.remove(1) + "");
result.add(randomizedSet.insert(2) + "");
result.add(randomizedSet.getRandom() + "");
List<String> expected =
new ArrayList<>(
Arrays.asList("null", "true", "false", "true", "1", "true", "false", "2"));
List<String> expected2 =
new ArrayList<>(
Arrays.asList("null", "true", "false", "true", "2", "true", "false", "2"));
if (random == 1) {
assertThat(result, equalTo(expected));
} else {
assertThat(result, equalTo(expected2));
}
}
}

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