Skip to content

Navigation Menu

Sign in
Appearance settings

Search code, repositories, users, issues, pull requests...

Provide feedback

We read every piece of feedback, and take your input very seriously.

Saved searches

Use saved searches to filter your results more quickly
Sign up
Appearance settings

[pull] master from youngyangyang04:master #491

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Merged
pull merged 8 commits into AlgorithmAndLeetCode:master from youngyangyang04:master
Oct 9, 2024
Merged
Changes from 2 commits
Commits
File filter

Filter by extension

Filter by extension
Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
2 changes: 1 addition & 1 deletion problems/0134.加油站.md
View file Open in desktop
Original file line number Diff line number Diff line change
Expand Up @@ -158,7 +158,7 @@ i从0开始累加rest[i],和记为curSum,一旦curSum小于零,说明[0, i

如果 curSum<0 说明 区间和1 + 区间和2 < 0, 那么 假设从上图中的位置开始计数curSum不会小于0的话,就是 区间和2>0。

区间和1 + 区间和2 < 0 同时 区间和2>0,只能说明区间和1 < 0, 那么就会从假设的箭头初就开始从新选择其实位置了。
区间和1 + 区间和2 < 0 同时 区间和2>0,只能说明区间和1 < 0, 那么就会从假设的箭头初就开始从新选择起始位置了。


**那么局部最优:当前累加rest[i]的和curSum一旦小于0,起始位置至少要是i+1,因为从i之前开始一定不行。全局最优:找到可以跑一圈的起始位置**。
Expand Down

AltStyle によって変換されたページ (->オリジナル) /