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Support (measure theory)

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Concept in mathematics

In mathematics, the support (sometimes topological support or spectrum) of a measure μ {\displaystyle \mu } {\displaystyle \mu } on a measurable topological space ( X , Borel ( X ) ) {\displaystyle (X,\operatorname {Borel} (X))} {\displaystyle (X,\operatorname {Borel} (X))} is a precise notion of where in the space X {\displaystyle X} {\displaystyle X} the measure "lives". It is defined to be the largest (closed) subset of X {\displaystyle X} {\displaystyle X} for which every open neighbourhood of every point of the set has positive measure.

Motivation

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A (non-negative) measure μ {\displaystyle \mu } {\displaystyle \mu } on a measurable space ( X , Σ ) {\displaystyle (X,\Sigma )} {\displaystyle (X,\Sigma )} is really a function μ : Σ [ 0 , + ] . {\displaystyle \mu :\Sigma \to [0,+\infty ].} {\displaystyle \mu :\Sigma \to [0,+\infty ].} Therefore, in terms of the usual definition of support, the support of μ {\displaystyle \mu } {\displaystyle \mu } is a subset of the σ-algebra Σ : {\displaystyle \Sigma :} {\displaystyle \Sigma :} supp ( μ ) := { A Σ | μ ( A ) 0 } ¯ , {\displaystyle \operatorname {supp} (\mu ):={\overline {\{A\in \Sigma ,円\vert ,円\mu (A)\neq 0\}}},} {\displaystyle \operatorname {supp} (\mu ):={\overline {\{A\in \Sigma ,円\vert ,円\mu (A)\neq 0\}}},} where the overbar denotes set closure. However, this definition is somewhat unsatisfactory: we use the notion of closure, but we do not even have a topology on Σ . {\displaystyle \Sigma .} {\displaystyle \Sigma .} What we really want to know is where in the space X {\displaystyle X} {\displaystyle X} the measure μ {\displaystyle \mu } {\displaystyle \mu } is non-zero. Consider two examples:

  1. Lebesgue measure λ {\displaystyle \lambda } {\displaystyle \lambda } on the real line R . {\displaystyle \mathbb {R} .} {\displaystyle \mathbb {R} .} It seems clear that λ {\displaystyle \lambda } {\displaystyle \lambda } "lives on" the whole of the real line.
  2. A Dirac measure δ p {\displaystyle \delta _{p}} {\displaystyle \delta _{p}} at some point p R . {\displaystyle p\in \mathbb {R} .} {\displaystyle p\in \mathbb {R} .} Again, intuition suggests that the measure δ p {\displaystyle \delta _{p}} {\displaystyle \delta _{p}} "lives at" the point p , {\displaystyle p,} {\displaystyle p,} and nowhere else.

In light of these two examples, we can reject the following candidate definitions in favour of the one in the next section:

  1. We could remove the points where μ {\displaystyle \mu } {\displaystyle \mu } is zero, and take the support to be the remainder X { x X μ ( { x } ) = 0 } . {\displaystyle X\setminus \{x\in X\mid \mu (\{x\})=0\}.} {\displaystyle X\setminus \{x\in X\mid \mu (\{x\})=0\}.} This might work for the Dirac measure δ p , {\displaystyle \delta _{p},} {\displaystyle \delta _{p},} but it would definitely not work for λ : {\displaystyle \lambda :} {\displaystyle \lambda :} since the Lebesgue measure of any singleton is zero, this definition would give λ {\displaystyle \lambda } {\displaystyle \lambda } empty support.
  2. By comparison with the notion of strict positivity of measures, we could take the support to be the set of all points with a neighbourhood of positive measure: { x X N x  open  such that  ( x N x  and  μ ( N x ) > 0 ) } {\displaystyle \{x\in X\mid \exists N_{x}{\text{ open}}{\text{ such that }}(x\in N_{x}{\text{ and }}\mu (N_{x})>0)\}} {\displaystyle \{x\in X\mid \exists N_{x}{\text{ open}}{\text{ such that }}(x\in N_{x}{\text{ and }}\mu (N_{x})>0)\}} (or the closure of this). It is also too simplistic: by taking N x = X {\displaystyle N_{x}=X} {\displaystyle N_{x}=X} for all points x X , {\displaystyle x\in X,} {\displaystyle x\in X,} this would make the support of every measure except the zero measure the whole of X . {\displaystyle X.} {\displaystyle X.}

However, the idea of "local strict positivity" is not too far from a workable definition.

Definition

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Let ( X , T ) {\displaystyle (X,T)} {\displaystyle (X,T)} be a topological space; let B ( T ) {\displaystyle B(T)} {\displaystyle B(T)} denote the Borel σ-algebra on X , {\displaystyle X,} {\displaystyle X,} i.e. the smallest sigma algebra on X {\displaystyle X} {\displaystyle X} that contains all open sets U T . {\displaystyle U\in T.} {\displaystyle U\in T.} Let μ {\displaystyle \mu } {\displaystyle \mu } be a measure on ( X , B ( T ) ) {\displaystyle (X,B(T))} {\displaystyle (X,B(T))}. Then the support (or spectrum) of μ {\displaystyle \mu } {\displaystyle \mu } is defined as the set of all points x {\displaystyle x} {\displaystyle x} in X {\displaystyle X} {\displaystyle X} for which every open neighbourhood N x {\displaystyle N_{x}} {\displaystyle N_{x}} of x {\displaystyle x} {\displaystyle x} has positive measure: supp ( μ ) := { x X N x T : ( x N x μ ( N x ) > 0 ) } . {\displaystyle \operatorname {supp} (\mu ):=\{x\in X\mid \forall N_{x}\in T\colon (x\in N_{x}\Rightarrow \mu (N_{x})>0)\}.} {\displaystyle \operatorname {supp} (\mu ):=\{x\in X\mid \forall N_{x}\in T\colon (x\in N_{x}\Rightarrow \mu (N_{x})>0)\}.}

Some authors prefer to take the closure of the above set. However, this is not necessary: see "Properties" below.

An equivalent definition of support is as the largest C B ( T ) {\displaystyle C\in B(T)} {\displaystyle C\in B(T)} (with respect to inclusion) such that every open set which has non-empty intersection with C {\displaystyle C} {\displaystyle C} has positive measure, i.e. the largest C {\displaystyle C} {\displaystyle C} such that: ( U T ) ( U C μ ( U C ) > 0 ) . {\displaystyle (\forall U\in T)(U\cap C\neq \varnothing \implies \mu (U\cap C)>0).} {\displaystyle (\forall U\in T)(U\cap C\neq \varnothing \implies \mu (U\cap C)>0).}

Signed and complex measures

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This definition can be extended to signed and complex measures. Suppose that μ : Σ [ , + ] {\displaystyle \mu :\Sigma \to [-\infty ,+\infty ]} {\displaystyle \mu :\Sigma \to [-\infty ,+\infty ]} is a signed measure. Use the Hahn decomposition theorem to write μ = μ + μ , {\displaystyle \mu =\mu ^{+}-\mu ^{-},} {\displaystyle \mu =\mu ^{+}-\mu ^{-},} where μ ± {\displaystyle \mu ^{\pm }} {\displaystyle \mu ^{\pm }} are both non-negative measures. Then the support of μ {\displaystyle \mu } {\displaystyle \mu } is defined to be supp ( μ ) := supp ( μ + ) supp ( μ ) . {\displaystyle \operatorname {supp} (\mu ):=\operatorname {supp} (\mu ^{+})\cup \operatorname {supp} (\mu ^{-}).} {\displaystyle \operatorname {supp} (\mu ):=\operatorname {supp} (\mu ^{+})\cup \operatorname {supp} (\mu ^{-}).}

Similarly, if μ : Σ C {\displaystyle \mu :\Sigma \to \mathbb {C} } {\displaystyle \mu :\Sigma \to \mathbb {C} } is a complex measure, the support of μ {\displaystyle \mu } {\displaystyle \mu } is defined to be the union of the supports of its real and imaginary parts.

Properties

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supp ( μ 1 + μ 2 ) = supp ( μ 1 ) supp ( μ 2 ) {\displaystyle \operatorname {supp} (\mu _{1}+\mu _{2})=\operatorname {supp} (\mu _{1})\cup \operatorname {supp} (\mu _{2})} {\displaystyle \operatorname {supp} (\mu _{1}+\mu _{2})=\operatorname {supp} (\mu _{1})\cup \operatorname {supp} (\mu _{2})} holds.

A measure μ {\displaystyle \mu } {\displaystyle \mu } on X {\displaystyle X} {\displaystyle X} is strictly positive if and only if it has support supp ( μ ) = X . {\displaystyle \operatorname {supp} (\mu )=X.} {\displaystyle \operatorname {supp} (\mu )=X.} If μ {\displaystyle \mu } {\displaystyle \mu } is strictly positive and x X {\displaystyle x\in X} {\displaystyle x\in X} is arbitrary, then any open neighbourhood of x , {\displaystyle x,} {\displaystyle x,} since it is an open set, has positive measure; hence, x supp ( μ ) , {\displaystyle x\in \operatorname {supp} (\mu ),} {\displaystyle x\in \operatorname {supp} (\mu ),} so supp ( μ ) = X . {\displaystyle \operatorname {supp} (\mu )=X.} {\displaystyle \operatorname {supp} (\mu )=X.} Conversely, if supp ( μ ) = X , {\displaystyle \operatorname {supp} (\mu )=X,} {\displaystyle \operatorname {supp} (\mu )=X,} then every non-empty open set (being an open neighbourhood of some point in its interior, which is also a point of the support) has positive measure; hence, μ {\displaystyle \mu } {\displaystyle \mu } is strictly positive. The support of a measure is closed in X , {\displaystyle X,} {\displaystyle X,}as its complement is the union of the open sets of measure 0. {\displaystyle 0.} {\displaystyle 0.}

In general the support of a nonzero measure may be empty: see the examples below. However, if X {\displaystyle X} {\displaystyle X} is a Hausdorff topological space and μ {\displaystyle \mu } {\displaystyle \mu } is a Radon measure, a Borel set A {\displaystyle A} {\displaystyle A} outside the support has measure zero: A X supp ( μ ) μ ( A ) = 0. {\displaystyle A\subseteq X\setminus \operatorname {supp} (\mu )\implies \mu (A)=0.} {\displaystyle A\subseteq X\setminus \operatorname {supp} (\mu )\implies \mu (A)=0.} The converse is true if A {\displaystyle A} {\displaystyle A} is open, but it is not true in general: it fails if there exists a point x supp ( μ ) {\displaystyle x\in \operatorname {supp} (\mu )} {\displaystyle x\in \operatorname {supp} (\mu )} such that μ ( { x } ) = 0 {\displaystyle \mu (\{x\})=0} {\displaystyle \mu (\{x\})=0} (e.g. Lebesgue measure). Thus, one does not need to "integrate outside the support": for any measurable function f : X R {\displaystyle f:X\to \mathbb {R} } {\displaystyle f:X\to \mathbb {R} } or C , {\displaystyle \mathbb {C} ,} {\displaystyle \mathbb {C} ,} X f ( x ) d μ ( x ) = supp ( μ ) f ( x ) d μ ( x ) . {\displaystyle \int _{X}f(x),円\mathrm {d} \mu (x)=\int _{\operatorname {supp} (\mu )}f(x),円\mathrm {d} \mu (x).} {\displaystyle \int _{X}f(x),円\mathrm {d} \mu (x)=\int _{\operatorname {supp} (\mu )}f(x),円\mathrm {d} \mu (x).}

The concept of support of a measure and that of spectrum of a self-adjoint linear operator on a Hilbert space are closely related. Indeed, if μ {\displaystyle \mu } {\displaystyle \mu } is a regular Borel measure on the line R , {\displaystyle \mathbb {R} ,} {\displaystyle \mathbb {R} ,} then the multiplication operator ( A f ) ( x ) = x f ( x ) {\displaystyle (Af)(x)=xf(x)} {\displaystyle (Af)(x)=xf(x)} is self-adjoint on its natural domain D ( A ) = { f L 2 ( R , d μ ) x f ( x ) L 2 ( R , d μ ) } {\displaystyle D(A)=\{f\in L^{2}(\mathbb {R} ,d\mu )\mid xf(x)\in L^{2}(\mathbb {R} ,d\mu )\}} {\displaystyle D(A)=\{f\in L^{2}(\mathbb {R} ,d\mu )\mid xf(x)\in L^{2}(\mathbb {R} ,d\mu )\}} and its spectrum coincides with the essential range of the identity function x x , {\displaystyle x\mapsto x,} {\displaystyle x\mapsto x,} which is precisely the support of μ . {\displaystyle \mu .} {\displaystyle \mu .}[1]

Examples

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Lebesgue measure

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In the case of Lebesgue measure λ {\displaystyle \lambda } {\displaystyle \lambda } on the real line R , {\displaystyle \mathbb {R} ,} {\displaystyle \mathbb {R} ,} consider an arbitrary point x R . {\displaystyle x\in \mathbb {R} .} {\displaystyle x\in \mathbb {R} .} Then any open neighbourhood N x {\displaystyle N_{x}} {\displaystyle N_{x}} of x {\displaystyle x} {\displaystyle x} must contain some open interval ( x ϵ , x + ϵ ) {\displaystyle (x-\epsilon ,x+\epsilon )} {\displaystyle (x-\epsilon ,x+\epsilon )} for some ϵ > 0. {\displaystyle \epsilon >0.} {\displaystyle \epsilon >0.} This interval has Lebesgue measure 2 ϵ > 0 , {\displaystyle 2\epsilon >0,} {\displaystyle 2\epsilon >0,} so λ ( N x ) 2 ϵ > 0. {\displaystyle \lambda (N_{x})\geq 2\epsilon >0.} {\displaystyle \lambda (N_{x})\geq 2\epsilon >0.} Since x R {\displaystyle x\in \mathbb {R} } {\displaystyle x\in \mathbb {R} } was arbitrary, supp ( λ ) = R . {\displaystyle \operatorname {supp} (\lambda )=\mathbb {R} .} {\displaystyle \operatorname {supp} (\lambda )=\mathbb {R} .}

Dirac measure

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In the case of Dirac measure δ p , {\displaystyle \delta _{p},} {\displaystyle \delta _{p},} let x R {\displaystyle x\in \mathbb {R} } {\displaystyle x\in \mathbb {R} } and consider two cases:

  1. if x = p , {\displaystyle x=p,} {\displaystyle x=p,} then every open neighbourhood N x {\displaystyle N_{x}} {\displaystyle N_{x}} of x {\displaystyle x} {\displaystyle x} contains p , {\displaystyle p,} {\displaystyle p,} so δ p ( N x ) = 1 > 0. {\displaystyle \delta _{p}(N_{x})=1>0.} {\displaystyle \delta _{p}(N_{x})=1>0.}
  2. on the other hand, if x p , {\displaystyle x\neq p,} {\displaystyle x\neq p,} then there exists a sufficiently small open ball B {\displaystyle B} {\displaystyle B} around x {\displaystyle x} {\displaystyle x} that does not contain p , {\displaystyle p,} {\displaystyle p,} so δ p ( B ) = 0. {\displaystyle \delta _{p}(B)=0.} {\displaystyle \delta _{p}(B)=0.}

We conclude that supp ( δ p ) {\displaystyle \operatorname {supp} (\delta _{p})} {\displaystyle \operatorname {supp} (\delta _{p})} is the closure of the singleton set { p } , {\displaystyle \{p\},} {\displaystyle \{p\},} which is { p } {\displaystyle \{p\}} {\displaystyle \{p\}} itself.

In fact, a measure μ {\displaystyle \mu } {\displaystyle \mu } on the real line is a Dirac measure δ p {\displaystyle \delta _{p}} {\displaystyle \delta _{p}} for some point p {\displaystyle p} {\displaystyle p} if and only if the support of μ {\displaystyle \mu } {\displaystyle \mu } is the singleton set { p } . {\displaystyle \{p\}.} {\displaystyle \{p\}.} Consequently, Dirac measure on the real line is the unique measure with zero variance (provided that the measure has variance at all).

A uniform distribution

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Consider the measure μ {\displaystyle \mu } {\displaystyle \mu } on the real line R {\displaystyle \mathbb {R} } {\displaystyle \mathbb {R} } defined by μ ( A ) := λ ( A ( 0 , 1 ) ) {\displaystyle \mu (A):=\lambda (A\cap (0,1))} {\displaystyle \mu (A):=\lambda (A\cap (0,1))} i.e. a uniform measure on the open interval ( 0 , 1 ) . {\displaystyle (0,1).} {\displaystyle (0,1).} A similar argument to the Dirac measure example shows that supp ( μ ) = [ 0 , 1 ] . {\displaystyle \operatorname {supp} (\mu )=[0,1].} {\displaystyle \operatorname {supp} (\mu )=[0,1].} Note that the boundary points 0 and 1 lie in the support: any open set containing 0 (or 1) contains an open interval about 0 (or 1), which must intersect ( 0 , 1 ) , {\displaystyle (0,1),} {\displaystyle (0,1),} and so must have positive μ {\displaystyle \mu } {\displaystyle \mu }-measure.

A nontrivial measure whose support is empty

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The space of all countable ordinals with the topology generated by "open intervals" is a locally compact Hausdorff space. The measure ("Dieudonné measure") that assigns measure 1 to Borel sets containing an unbounded closed subset and assigns 0 to other Borel sets is a Borel probability measure whose support is empty. [2]

A nontrivial measure whose support has measure zero

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On a compact Hausdorff space the support of a non-zero measure is always non-empty, but may have measure 0. {\displaystyle 0.} {\displaystyle 0.} An example of this is given by adding the first uncountable ordinal Ω {\displaystyle \Omega } {\displaystyle \Omega } to the previous example: the support of the measure is the single point Ω , {\displaystyle \Omega ,} {\displaystyle \Omega ,} which has measure 0. {\displaystyle 0.} {\displaystyle 0.}

References

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  1. ^ Mathematical methods in Quantum Mechanics with applications to Schrödinger Operators
  2. ^ Measure theory, Example 7.1.3
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