2006 Dutch Open – Singles
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| Singles | |
|---|---|
| 2006 Dutch Open | |
| Final | |
| Champion | Serbia Novak Djokovic |
| Runner-up | Chile Nicolás Massú |
| Score | 7–6(7–5), 6–4 |
| Details | |
| Draw | 32 |
| Seeds | 8 |
| Events | |
2006 tennis event results
Main article: 2006 Dutch Open (tennis)
Fernando González was the defending champion, but did not participate this year.
Novak Djokovic won the tournament (his first career title[1] ), beating Nicolás Massú in the final, 7–6(7–5), 6–4.
Seeds
[edit ]- Argentina Guillermo Coria (semifinals, retired due to a right shoulder injury)
- France Paul-Henri Mathieu (second round)
- Serbia Novak Djokovic (champion)
- Chile Nicolás Massú (final)
- Spain Carlos Moyá (quarterfinals)
- Spain Alberto Martín (quarterfinals)
- Italy Daniele Bracciali (second round)
- France Julien Benneteau (first round)
Draw
[edit ]Key
[edit ]- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
Finals
[edit ] Semifinals
Final
1
Argentina Guillermo Coria
2
0r
3
Serbia Novak Djokovic
6
1
3
Serbia Novak Djokovic
77
6
4
Chile Nicolás Massú
65
4
4
Chile Nicolás Massú
6
6
Top half
[edit ] First round
Second round
Quarterfinals
Semifinals
8
France J Benneteau
3
3
Bottom half
[edit ] First round
Second round
Quarterfinals
Semifinals
2
France P-H Mathieu
6
6
References
[edit ]- ^ "Djokovic's Breakthrough: 10 Years On..." Association of Tennis Professionals (ATP). 21 July 2016.