2006 Croatia Open Umag – Singles
Appearance
From Wikipedia, the free encyclopedia
Singles | |
---|---|
2006 Croatia Open Umag | |
Final | |
Champions | Switzerland Stan Wawrinka |
Runners-up | Serbia Novak Djokovic |
Score | 6–6 (1–3) Ret. |
Details | |
Draw | 32 (4 Q / 3 WC ) |
Seeds | 8 |
Events | |
2006 tennis event results
Main article: 2006 Croatia Open Umag
Stan Wawrinka won his first ATP title, after Novak Djokovic retired in the final while leading 3–1 in the first-set tiebreak.[1]
Guillermo Coria was the defending champion, but lost in the first round to Robin Vik.
Seeds
[edit ]- Spain David Ferrer (withdrew)[2]
- Spain Juan Carlos Ferrero (first round)
- Argentina Guillermo Coria (first round)
- Serbia Novak Djokovic (final, retired due to breathing problems)
- Spain Carlos Moyá (semifinals)
- Spain Alberto Martín (first round)
- France Julien Benneteau (first round)
- Italy Filippo Volandri (semifinals)
Draw
[edit ]Key
[edit ]- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
Finals
[edit ] Semifinals
Final
5
Spain Carlos Moyá
1
5
4
Serbia Novak Djokovic
6
7
4
Serbia Novak Djokovic
63r
Switzerland Stan Wawrinka
7
2
6
8
Italy Filippo Volandri
5
6
4
Top half
[edit ] First round
Second round
Quarterfinals
Semifinals
7
France J Benneteau
6
3
2
Bottom half
[edit ] First round
Second round
Quarterfinals
Semifinals
2
Spain JC Ferrero
64
77
5
References
[edit ]- ^ "Wawrinka wins Croatia Open when Djokovic retires". USA Today. 30 July 2006. Retrieved 17 February 2014.
- ^ "Defending champion Coria faces Vik at Umag tennis Tuesday". ESPN. 25 July 2006. Retrieved 17 February 2014.