1999 Paris Open – Doubles
From Wikipedia, the free encyclopedia
| Doubles | |
|---|---|
| 1999 Paris Open | |
| Final | |
| Champions | |
| Runners-up | |
| Score | 7–6(9–7), 7–5 |
| Details | |
| Draw | 24 |
| Seeds | 8 |
| Events | |
1999 tennis event results
Main article: 1999 Paris Open
Mahesh Bhupathi and Leander Paes were the defending champions. Bhupathi partnered Andrew Florent this year, losing in the second round. Paes did not participate this year.
Sébastien Lareau and Alex O'Brien won in the final 7–6(9–7), 7–5, against Paul Haarhuis and Jared Palmer.
Seeds
[edit ]All seeds receive a bye into the second round.
- Canada Sébastien Lareau / United States Alex O'Brien (champions)
- Netherlands Paul Haarhuis / United States Jared Palmer (final)
- Sweden Jonas Björkman / Zimbabwe Byron Black (second round)
- Australia Todd Woodbridge / Australia Mark Woodforde (quarterfinals)
- Zimbabwe Wayne Black / Australia Sandon Stolle (second round)
- South Africa Ellis Ferreira / United States Rick Leach (semifinals)
- France Olivier Delaître / France Fabrice Santoro (second round)
- India Mahesh Bhupathi / Australia Andrew Florent (second round)
Draw
[edit ]Key
[edit ]- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
Finals
[edit ] Semifinals
Final
Top half
[edit ] First round
Second round
Quarterfinals
Semifinals
1
6
6
2
6
3
2
4
6
4
6
1
77
6
7
4
3
1
6
6
3
3
6
4
WC
4
3
1
6
4
6
2
5
6
1
6
2
6
7
4
77
6
Bottom half
[edit ] First round
Second round
Quarterfinals
Semifinals
6
4
78
6
WC
3
4
6
66
4
6
6
6
66
6
77
WC
1
1r
4
78
4
63
6
4
6
2
2
6
2
6
8
1
3
77
6
6
6
Q
63
3
6
2
5
4
2
2
2
6
7
2
77
77