1999 Dubai Tennis Championships – Singles
Appearance
From Wikipedia, the free encyclopedia
Singles | |
---|---|
1999 Dubai Tennis Championships | |
Final | |
Champion | France Jérôme Golmard |
Runner-up | Germany Nicolas Kiefer |
Score | 6–4, 6–2 |
Details | |
Draw | 32 |
Seeds | 8 |
Events | |
1999 tennis event results
Main article: 1999 Dubai Tennis Championships
Àlex Corretja was the defending champion,[1] but lost in the first round to Andrew Ilie.
Jérôme Golmard won the title, defeating Nicolas Kiefer 6–4, 6–2 in the final.[2]
Seeds
[edit ]- Spain Àlex Corretja (first round)
- Spain Carlos Moyá (semifinals)
- United Kingdom Tim Henman (quarterfinals)
- United Kingdom Greg Rusedski (second round)
- Slovakia Karol Kučera (second round)
- Spain Albert Costa (second round)
- Spain Félix Mantilla (quarterfinals)
- Brazil Gustavo Kuerten (quarterfinals)
Draw
[edit ]Key
[edit ]- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
Finals
[edit ] Semifinals
Final
Australia Andrew Ilie
3
66
Germany Nicolas Kiefer
6
78
France Jérôme Golmard
6
6
France Jérôme Golmard
4
7
6
2
Spain Carlos Moyá
6
5
3
Top half
[edit ] First round
Second round
Quarterfinals
Semifinals
1
Spain À Corretja
6
4
610
Bottom half
[edit ] First round
Second round
Quarterfinals
Semifinals
References
[edit ]- ^ "Corretja Takes Dubai Open Title". Associated Press. 15 February 1998. Archived from the original on 2020年09月02日. Retrieved 4 May 2014.
- ^ "Golmard defeats Kiefer at Dubai for first Tour win". Sports Illustrated. 14 February 1999. Archived from the original on 25 March 2014. Retrieved 4 May 2014.