1998 Gold Flake Open – Doubles
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| Doubles | |
|---|---|
| 1998 Gold Flake Open | |
| Final | |
| Champions | India Mahesh Bhupathi India Leander Paes |
| Runners-up | France Olivier Delaître Belarus Max Mirnyi |
| Score | 6–7, 6–3, 6–2 |
| Events | |
1998 tennis event results
Main article: 1998 Gold Flake Open
Mahesh Bhupathi and Leander Paes were the defending champions. They successfully defended their title, defeating Olivier Delaître and Max Mirnyi in the final 6–7, 6–3, 6–2.
Seeds
[edit ]- Australia Todd Woodbridge / Australia Mark Woodforde (quarterfinals)
- India Mahesh Bhupathi / India Leander Paes (champions)
- United States Jeff Salzenstein / United States Jonathan Stark (first round)
- France Olivier Delaître / Belarus Max Mirnyi (final)
Draw
[edit ]Key
[edit ]- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
Draw
[edit ] First round
Quarterfinals
Semifinals
Final
United States D DiLucia
Australia P Tramacchi 2 2 1 Australia T Woodbridge
Australia M Woodforde 6 1
Australia P Tramacchi 2 2 1 Australia T Woodbridge
Australia M Woodforde 6 1
Q
South Africa D Nainkin
South Africa W Whitehouse 7 6 Q South Africa D Nainkin
South Africa W Whitehouse 6 4 6
South Africa W Whitehouse 7 6 Q South Africa D Nainkin
South Africa W Whitehouse 6 4 6
3
United States J Salzenstein
United States J Stark 6 4 United Kingdom B Cowan
Switzerland F Veglio 6 1 6
United States J Stark 6 4 United Kingdom B Cowan
Switzerland F Veglio 6 1 6