1998 Chevrolet Cup – Doubles
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| Doubles | |
|---|---|
| 1998 Chevrolet Cup | |
| Final | |
| Champions | Argentina Mariano Hood Argentina Sebastián Prieto |
| Runners-up | Italy Massimo Bertolini United States Devin Bowen |
| Score | 7–6, 6–7, 7–6 |
| Events | |
1998 tennis event results
Main article: 1998 Chevrolet Cup
Hendrik Jan Davids and Andrew Kratzmann were the defending champions, but did not participate this year.
Mariano Hood and Sebastián Prieto won the title, defeating Massimo Bertolini and Devin Bowen 7–6, 6–7, 7–6 in the final.
Seeds
[edit ]- Argentina Daniel Orsanic / Mexico David Roditi (quarterfinals)
- Spain Julián Alonso / Ecuador Nicolás Lapentti (first round)
- Argentina Mariano Hood / Argentina Sebastián Prieto (champions)
- United States Brandon Coupe / South Africa Paul Rosner (first round)
Draw
[edit ]Key
[edit ]- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
Draw
[edit ] First round
Quarterfinals
Semifinals
Final
South Africa L Bale
United Kingdom D Sapsford 7 4 6 South Africa L Bale
United Kingdom D Sapsford 6 6 4
United Kingdom D Sapsford 7 4 6 South Africa L Bale
United Kingdom D Sapsford 6 6 4