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1976 Wimbledon Championships – Girls' singles

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Girls' singles
1976 Wimbledon Championships
Final
ChampionSoviet Union Natasha Chmyreva
Runner-upSouth Africa Marise Kruger
Score6–3, 2–6, 6–1
Details
Draw32
Events
Singles men women boys girls
Doubles men women mixed boys girls
← 1975 · Wimbledon Championships · 1977 →
1976 tennis event results

Natasha Chmyreva successfully defended her title, defeating Marise Kruger in the final, 6–3, 2–6, 6–1 to win the girls' singles tennis title at the 1976 Wimbledon Championships.[1]

Draw

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Key

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Finals

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Semifinals Final
                   

Top half

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First round Second round Quarterfinals Semifinals
Brazil Paola Sessarego 2 3 Soviet Union N Chmyreva 6 6
France Perrine du Puy 8 3 6 France P du Puy 0 1
Poland Małgorzata Sieradzka 6 6 2 Soviet Union N Chmyreva 2 6 6
New Zealand Sally Chapman 4 3 United States L Antonoplis 6 3 6
Socialist Federal Republic of Yugoslavia Nenni Delmestre 0 1 Canada N Marois 0 6 2
Canada N Marois 6 6 Soviet Union N Chmyreva 6 6
Egypt SA El Marashi 0 1 United Kingdom M Tyler 6 6
Republic of Ireland Louise Tuff 2 2 Norway E Torkildsen 0 1
Norway E Torkildsen 6 6 United Kingdom M Tyler 6 6
Portugal M Lencastro 1 6 2 Denmark HH Thomsen 2 2
Denmark HH Thomsen 6 4 6

Bottom half

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First round Second round Quarterfinals Semifinals
Japan Y Watanabe 6 6
India SJ Jones 3 1 Japan Y Watanabe 1 1
Finland T Ojala 3 3 Australia M Pekovitch 6 6
Australia Michelle Pekovitch 6 6 Australia M Pekovitch 1 6
Jamaica LY Sam 6 6 South Africa M Kruger 6 8
Belgium Martine Van De Winkel 0 0 South Africa M Kruger 6 6
Israel Hagit Zubary 3 3 Netherlands I Korsten 3 3
Bulgaria Marina Kondova 1 0 Czechoslovakia R Maršíková 6 6

References

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  1. ^ "Girls' Singles Finals 1947-2017". wimbledon.com. Wimbledon Championships . Retrieved 13 August 2017.
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