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1974 Wimbledon Championships – Girls' singles

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Girls' singles
1974 Wimbledon Championships
Final
ChampionSocialist Federal Republic of Yugoslavia Mima Jaušovec
Runner-upRomania Mariana Simionescu
Score7–5, 6–4
Details
Draw25
Events
Singles men women boys girls
Doubles men women mixed boys girls
← 1973 · Wimbledon Championships · 1975 →
1974 tennis event results

Mima Jaušovec defeated Mariana Simionescu in the final, 7–5, 6–4 to win the girls' singles tennis title at the 1974 Wimbledon Championships.[1]

Draw

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Key

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Finals

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Semifinals Final
                   

Top half

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First round Second round Quarterfinals Semifinals
Austria E Celigoj 0 4
Israel R Heller 1 4 Switzerland A Rüegg 2 0
Republic of Ireland Bernadette Davy 0 4 Romania M Simionescu 6 6
Spain María Mateo 3 4 Romania M Simionescu 6 5 6
Belgium A Gerain Belgium A Gerain 4 2
Brazil Léa Rios de Almeida 4 6 4 West Germany I Pohmann 6 6
West Germany Inge Pohmann 6 3 6

Bottom half

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First round Second round Quarterfinals Semifinals
Mexico Jeannine Balbiers 9 3 6 Mexico J Balbiers 1 1
Norway E Torkildsen 7 6 3 United Kingdom S Barker 6 6
Finland Elina Durchman 1 0 Sweden H Anliot 6 6
Canada DA Mushlian 6 3 2 Netherlands B Sluyter 0 4
Netherlands B Sluyter 4 6 6 United Kingdom S Barker 4 4
United Arab Emirates Hoda Baligh 0 0
France Christine Gimmig 3 3

References

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  1. ^ "Girls' Singles Finals 1947-2017". wimbledon.com. Wimbledon Championships . Retrieved 13 August 2017.
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