1899 Iowa gubernatorial election

← 1897 November 7, 1899 1901 →


Nominee	L. M. Shaw	Frederick Edward White
Party	Republican	Democratic
Popular vote	239,464	183,301
Percentage	55.26%	42.30%

County results
Shaw: 40-50% 50-60% 60-70% 70-80%
White: 40-50% 50-60%

Governor before election

L. M. Shaw
Republican

Elected Governor

L. M. Shaw
Republican

Elections in Iowa

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Cedar Rapids

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v
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The 1899 Iowa gubernatorial election was held on November 7, 1899. Incumbent Republican L. M. Shaw defeated Democratic nominee Frederick Edward White with 55.26% of the vote.

General election

[edit ]

Candidates

[edit ]

Major party candidates

L. M. Shaw, Republican
Frederick Edward White, Democratic

Other candidates

Marshall W. Atwood, Prohibition
Charles Lloyd, People's
M. J. Kremer, Socialist Labor
C. C. Heacock, United Christian

Results

[edit ]

1899 Iowa gubernatorial election^[1]
Party		Candidate	Votes
Republican	L. M. Shaw (incumbent)	239,464	55.26%
Democratic	Frederick Edward White	183,301	42.30%
Prohibition	Marshall W. Atwood	7,639	1.76%
Populist	Charles Lloyd	1,698	0.39%
Socialist Labor	M. J. Kremer	757	0.18%
Independent	C. C. Heacock	484	0.11%
Majority			56,163
Turnout
Republican hold		Swing

References

[edit ]

^ Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN 9781483380353 . Retrieved August 7, 2020.

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