1867 Iowa gubernatorial election
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1867 Iowa gubernatorial election
| Nominee | Samuel Merrill | Charles Mason |
|---|---|---|
| Party | Republican | Democratic |
| Popular vote | 90,204 | 62,966 |
| Percentage | 58.88% | 41.10% |
County results
Merrill: 50-60% 60-70% 70-80% 80-90% 90-100%
Mason: 50-60% 60-70%
No Data/Votes:
Merrill: 50-60% 60-70% 70-80% 80-90% 90-100%
Mason: 50-60% 60-70%
No Data/Votes:
The 1867 Iowa gubernatorial election was held on October 8, 1867. Republican nominee Samuel Merrill defeated Democratic nominee Charles Mason with 58.88% of the vote.
General election
[edit ]Candidates
[edit ]- Samuel Merrill, Republican
- Charles Mason, Democratic
Results
[edit ]| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | Samuel Merrill | 90,204 | 58.88% | ||
| Democratic | Charles Mason | 62,966 | 41.10% | ||
| Majority | 27,238 | ||||
| Turnout | |||||
| Republican hold | Swing | ||||
References
[edit ]- ^ Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN 9781483380353 . Retrieved June 5, 2021.