Trying to understand vhdl led blinking code

Question

I have a led blinking code for MachXO2 breakout board written in VHDL. Actually I am new to VHDL.

I am not able to understand the meaning of these lines:

--internal oscillator
 COMPONENT OSCH
 GENERIC(
 NOM_FREQ: string := "53.20");
 PORT( 
 STDBY : IN STD_LOGIC;
 OSC : OUT STD_LOGIC;
 SEDSTDBY : OUT STD_LOGIC);
 END COMPONENT;
BEGIN
 --internal oscillator
 OSCInst0: OSCH
 GENERIC MAP (NOM_FREQ => "53.20")
 PORT MAP (STDBY => '0', OSC => clk, SEDSTDBY => OPEN);

Can you please tell me What these lines are doing?

Answer 1

These lines use an externally defined component, called OSCH, that magically provides a clock on the osc output as long as the stdby input is low.

The osc output is then connected to the clk signal and the stdby input connected to 0 (i.e. the switch-off function is not used.

• user16222: you should find a package called OSCH which (if you are lucky its vhd) will show you the lower-level logic associated with that. I find it helps with VHDL to think of it like wiring chips up and a component is an IC and portmaping is wiring