Benutzer:Kriegerdaemon

Test...

${\displaystyle C=9Nk_{B}({\frac {T}{\theta _{D}}})^{3}\int _{0}^{\theta _{D}/T}{\frac {x^{4}e^{x}}{(e^{x}-1)^{2}}}dx}${\displaystyle C=9Nk_{B}({\frac {T}{\theta _{D}}})^{3}\int _{0}^{\theta _{D}/T}{\frac {x^{4}e^{x}}{(e^{x}-1)^{2}}}dx}

${\displaystyle \theta _{D}={\frac {h}{k_{B}}}\left({\frac {6\pi ^{2}N}{V}}\right)^{1/3}}${\displaystyle \theta _{D}={\frac {h}{k_{B}}}\left({\frac {6\pi ^{2}N}{V}}\right)^{1/3}}

${\displaystyle C=9\cdot N\cdot k_{B}({\frac {T}{{\frac {h}{k_{B}}}\left({\frac {6\cdot \pi ^{2}\cdot N}{V}}\right)^{1/3}}})^{3}\int _{0}^{{\frac {h}{k_{B}}}\left({\frac {6\cdot \pi ^{2}\cdot N}{V}}\right)^{1/3}/T}{\frac {x^{4}\cdot e^{x}}{(e^{x}-1)^{2}}}dx}${\displaystyle C=9\cdot N\cdot k_{B}({\frac {T}{{\frac {h}{k_{B}}}\left({\frac {6\cdot \pi ^{2}\cdot N}{V}}\right)^{1/3}}})^{3}\int _{0}^{{\frac {h}{k_{B}}}\left({\frac {6\cdot \pi ^{2}\cdot N}{V}}\right)^{1/3}/T}{\frac {x^{4}\cdot e^{x}}{(e^{x}-1)^{2}}}dx}