I have the following dictionary:
top = {'aaaa': {'βΉ': 7, 'πΉ': 12, 'π‘': 6},
'bbbb': {'π': 2, 'π': 2, 'π': 2},
'cccc': {'βΉ': 5, 'π': 3, 'π': 3},
'dddd': {'π': 8, 'π': 7, 'π€': 3},
'eeee': {'βΊ': 3, 'π': 5, 'π': 4},
'ffff': {'βΉ': 5, 'π': 5, 'π’': 5}}
Each 'aaaa' or 'bbbb' is the user's name, and his values is the emoji he is using the most. I want to plot a decent looking graph to visualize. After a few tries, this is my best work:
with the code:
import matplotlib.pyplot as plt
def top_emoji(top):
fig, ax = plt.subplots(figsize=(8, 5))
y = 9
level = 0
start = 9
for name, dictionary in top.items():
ax.text(start, y - level, name, fontsize=20)
x = 3
for emoj in dictionary.keys():
ax.text(start - x, y - level, emoj, fontname='Segoe UI Emoji', fontsize=20)
x += 1
level += 1
ax.axis([0, 10, 0, 10])
ax.get_xaxis().set_visible(False)
ax.get_yaxis().set_visible(False)
ax.axis('off')
plt.show()
Which is terrible in my opinion. Any recommendations for improvements will be much appreciated.
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\$\begingroup\$ Just to be clear... the scores are irrelevant? And it's OK to present each user's emojis in any order? \$\endgroup\$200_success– 200_success2017εΉ΄11ζ18ζ₯ 18:44:14 +00:00Commented Nov 18, 2017 at 18:44
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\$\begingroup\$ Well I rather put the highest score first, closest to the person's name, but right now it doesn't really bother me. \$\endgroup\$sheldonzy– sheldonzy2017εΉ΄11ζ18ζ₯ 18:45:25 +00:00Commented Nov 18, 2017 at 18:45
1 Answer 1
Your code might be a bit clearer without level & start, preferring to manipulate just x & y.
You might write a sorting helper function, and change the emoj
loop to this:
for x, emoj in enumerate(emoj_by_score(dictionary)):
You have some hard coded values that you could derive by inspecting the top
input argument. On the whole, it doesn't seem so terrible. It is reasonably clear.
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