• # ORM pour sqlite

    Posté par . En réponse au message débutant. Évalué à 1.

    J'utiliser SQLObject http://sqlobject.org/ c'est vraiment efficace.

    SQLObject is a popular Object Relational Manager for providing an object interface to your database, with tables as classes, rows as instances, and columns as attributes.

    SQLObject includes a Python-object-based query language that makes SQL more abstract, and provides substantial database independence for applications.