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std::chrono::year::operator++, std::chrono::year::operator--

From cppreference.com
< cpp‎ | chrono‎ | year
 
 
Date and time library
(C++11)
(C++20)
(C++11)
(C++11)
(C++11)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)(C++20)
(C++20)(C++20)
(C++20)
(C++20)
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(C++20)
(C++20)
(C++20)
(C++20)(C++20)
(C++20)

 
 
constexpr std::chrono::year & operator++() noexcept;
(1) (since C++20)
constexpr std::chrono::year operator++( int ) noexcept;
(2) (since C++20)
constexpr std::chrono::year & operator--() noexcept;
(3) (since C++20)
constexpr std::chrono::year operator--( int ) noexcept;
(4) (since C++20)

Adds or subtracts 1 from the year value.

1,2) Performs *this += std::chrono::years {1};.
3,4) Performs *this -= std::chrono::years {1};.

[edit] Parameters

(none)

[edit] Return value

1,3) A reference to this year after modification.
2,4) A copy of the year made before modification.

[edit] Notes

If the result would be outside the range [-3276732767], the actual stored value is unspecified.

[edit] Example

Run this code
#include <chrono>
#include <iostream>
 
int main()
{
 std::cout << std::boolalpha ;
 
 std::chrono::year y{2020};
 std::cout << (++y == std::chrono::year (2021)) << ' ';
 std::cout << (--y == std::chrono::year (2020)) << '\n';
 
 using namespace std::literals::chrono_literals;
 y = 32767y;
 y++; //← unspecified, see ↑ Notes ↑
 std::cout << static_cast<int>(y) << '\n';
}

Possible output:

true true
-32768

[edit] See also

adds or subtracts a number of years from a year
(public member function) [edit]
performs arithmetic on years
(function) [edit]
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