Array with a function that returns a value

Question

I have the following constant :

 const getActionsList = {
 listActions: [
 '$http',
 '$route',
 '$q',
 '$location',
 function($http, $route, $q, $location) {
 const id = $route.current.params.id;
 const deferred = $q.defer();
 $http.get('/test/' + id).then(
 function(result) {
 if (result.data.length > 0) {
 deferred.resolve(result.data);
 } else {
 var urlRedirect = '/';
 $location.url(urlRedirect).replace();
 }
 },
 function(result) {
 deferred.reject(result);
 }
 );
 return deferred.promise;
 }
 ]
 };

the function that is in getActionsList must return a value.

and I would like when I call it in another function that it returns a value rather than a function

var menu = function() {
 return {
 mediaType: function() {
 return getActionsList[4];//should return a value rather than a function 
 }
 };
 };

how to get getActionsList [4] to return a value ?

Answer 1

May be like this

return getActionsList.listActions[4]()

but parameters need to be passed

Answer 2

Simply have mediaType use the function instead of return the function:

var menu = function() {
 return {
 mediaType: getActionsList[4];//should return a value rather than a function
 };
};

Answer 3

getActionsList[4]

will return a value of array - and it's a function. You need to invoke the function, to get result :)

getActionsList[4]()

Answer 4

Try my code:

var menu = function() {
 return {
 mediaType: (function() {
 return getActionsList.listActions[4](); //should return a value rather than a function
 })()
 };
};

get ActionsList is an object and in that object you put an array of listActions.

Now in your function expression menu, you want to return a mediaType and that should an anonymous function. You need to invoke the function to return value. You also need to invoke the listActions[4]. So you need to put it in this way listActions4. And since that listAction was inside of an object getActionsList that's why it will now be getActionsList.listActions4