Free presentation
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In algebra, a free presentation of a module M over a commutative ring R is an exact sequence of R-modules:
- {\displaystyle \bigoplus _{i\in I}R\ {\overset {f}{\to }}\ \bigoplus _{j\in J}R\ {\overset {g}{\to }}\ M\to 0.}
Note the image under g of the standard basis generates M. In particular, if J is finite, then M is a finitely generated module. If I and J are finite sets, then the presentation is called a finite presentation; a module is called finitely presented if it admits a finite presentation.
Since f is a module homomorphism between free modules, it can be visualized as an (infinite) matrix with entries in R and M as its cokernel.
A free presentation always exists: any module is a quotient of a free module: {\displaystyle F\ {\overset {g}{\to }}\ M\to 0}, but then the kernel of g is again a quotient of a free module: {\displaystyle F'\ {\overset {f}{\to }}\ \ker g\to 0}. The combination of f and g is a free presentation of M. Now, one can obviously keep "resolving" the kernels in this fashion; the result is called a free resolution. Thus, a free presentation is the early part of the free resolution.
A presentation is useful for computation. For example, since tensoring is right-exact, tensoring the above presentation with a module, say N, gives:
- {\displaystyle \bigoplus _{i\in I}N\ {\overset {f\otimes 1}{\to }}\ \bigoplus _{j\in J}N\to M\otimes _{R}N\to 0.}
This says that {\displaystyle M\otimes _{R}N} is the cokernel of {\displaystyle f\otimes 1}. If N is also a ring (and hence an R-algebra), then this is the presentation of the N-module {\displaystyle M\otimes _{R}N}; that is, the presentation extends under base extension.
For left-exact functors, there is for example
Proposition—Let F, G be left-exact contravariant functors from the category of modules over a commutative ring R to abelian groups and θ a natural transformation from F to G. If {\displaystyle \theta :F(R^{\oplus n})\to G(R^{\oplus n})} is an isomorphism for each natural number n, then {\displaystyle \theta :F(M)\to G(M)} is an isomorphism for any finitely-presented module M.
Proof: Applying F to a finite presentation {\displaystyle R^{\oplus n}\to R^{\oplus m}\to M\to 0} results in
- {\displaystyle 0\to F(M)\to F(R^{\oplus m})\to F(R^{\oplus n}).}
This can be trivially extended to
- {\displaystyle 0\to 0\to F(M)\to F(R^{\oplus m})\to F(R^{\oplus n}).}
The same thing holds for {\displaystyle G}. Now apply the five lemma. {\displaystyle \square }
See also
[edit ]References
[edit ]- Eisenbud, David, Commutative Algebra with a View Toward Algebraic Geometry, Graduate Texts in Mathematics, 150, Springer-Verlag, 1995, ISBN 0-387-94268-8.