RE: Lua 5 iterator question
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- Subject: RE: Lua 5 iterator question
- From: RLake@...
- Date: 2004年2月12日 18:59:42 -0500
The simplest way to iterate through
a string a line at a time (if you don't care about blank lines):
for line in string.gfind(str, "[^\n]+")
do print(string.format("%q", line)) end
This will skip empty lines, but not
lines with only whitespace.
There are variations on the theme. For
example, the following will trim whitespace from
both ends of each line, and just return
non-blank lines:
for line in string.gfind(str, "%s*([^\n]*%S)%s*\n?")
do
print(string.format("%q",
line))
end
I suppose that doesn't help you learn
how to write iterators, though :)
Here is a simple iterator which returns
a vector in pairs:
function two_at_a_time(v)
local i = 1
local function helper(v)
local a, b
a, b, i = v[i], v[i +
1], i + 2
if a and b then return
a, b end
end
return helper, v
end
Note that we cannot use the iterator
variable here because we don't want
it to pop out during the for loop, the
expected pattern would be:
for first, second in two_at_a_time(vec)
do
print(first * second)
end
But if we actually wanted the index,
we could write the iterator
more simply, and more efficiently:
do
local function helper(v, i)
local i, a, b = i + 2,
v[i], v[i + 1]
if a and b then return
i, a, b end
end
function two_at_a_time(v) return
helper, v, 1