RE: Lua 5 iterator question

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Subject: RE: Lua 5 iterator question
From: "Bilyk, Alex" <ABilyk@...>
Date: 2004年2月12日 11:19:25 -0800

Title: Lua 5 iterator question

It's more like this

----------- CUT HERE -----------------------------

function lineIterator(str)
local pos
local function lineIterate()
if not pos then
pos = 0
end
local s1 = string.find(str, "\n", pos, true)
local line
if not s1 then
pos = nil
else
line = string.sub(str, pos, s1-1)
pos = s1 + 1
end
return line
end
return lineIterate
end

s = [[
***hello
***this
***is
***a
***string
]]

s1 = [[
###
@@@
]]

for line in lineIterator(s) do
print(line)
for line2 in lineIterator(s1) do

print(line2)

end
end

----------- CUT HERE -----------------------------

I am sure this could be more optimal as the iterator creates new function on every iteration.

Alex

-----Original Message-----
From: Stewart, Joseph [mailto:Joseph.Stewart@sciatl.com]
Sent: Thursday, February 12, 2004 7:06 AM
To: 'Lua list'
Subject: Lua 5 iterator question

Hello all,

I've read the lua 5 documentation and looked at the iterator tutorial, but I'm still stumped on how to create an interator function that will step through a string a line at a time.

Here's the code I've come up with so far (from memory, the code is a home):

function lineIterate(state,n)
local s1
s1 = string.find(n, "\n", state)
if not s1 then return nil end
return s1+1, string.sub(n, state, s1)
end

s = [[hello
this
is
a
string]]

for i,v in lineIterate(i, s) do print(v) end

Am I way off base? Thanks for all suggestions!
-joe

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