Introduction to Programming with C++
Introduction to Programming with C++
3rd Edition
ISBN: 9780133252811
Author: Y. Daniel Liang
Publisher: Prentice Hall
Expert Solution & Answer
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Chapter 4, Problem 1CP

a.

Explanation of Solution

Given: The value of PI is 3.14159 and E has the value 2.71828.

To find:Â That what will be the result of the function, sqrt(4.0).

Solution:

The function, sqrt(4.0), will evaluate to 2. The sqrt function will perform the square root of the number which is passed in the function parameter. It is a library function belonging to the header, cmath.

b.

Explanation of Solution

Given: The value of PI is 3.14159 and E has the value 2.71828.

To find:Â That what will be the result of the function, sin(2*PI).

Solution:

The function, sin(2*PI) , evaluates to 0. The sin function returns the final value of the sine of the angle which is passed in the parameter. It is a library function belonging to the header, cmath. It returns the sine of angle in radians.

c.

Explanation of Solution

Given: The value of PI is 3.14159 and E has the value 2.71828.

To find:Â That what will be the result of the function, cos(2*PI).

Solution:

The function, cos(2*PI), evaluates to 1. The cosine function returns the final value of the cosine of the angle which is passed in the parameter. It is a library function belonging to the header, cmath. It returns the cosine of angle in radians.

d.

Explanation of Solution

Given: The value of PI is 3.14159 and E has the value 2.71828.

To find:Â That what will be the result of the function, pow(2.0, 2).

Solution:

The function, pow(2.0, 2), will return the value 4. It computes the base number which is raised to the power of the exponent number. It is a library function belonging to the header, cmath. It follows the syntax pow(base, exponent).

e.

Explanation of Solution

Given: The value of PI is 3.14159 and E has the value 2.71828.

To find:Â That what will be the result of the function, log(E).

Solution:

The function, log(E), will evaluate to 1. It returns the natural logarithmic value of the argument which is passed as the parameter. The parameters can belong to any data type, like int, float, double or long-double.

f.

Explanation of Solution

Given: The value of PI is 3.14159 and E has the value 2.71828.

To find:Â That what will be the result of the function, exp(1.0).

Solution:

The function, exp(1.0), will return the value 2. It returns the exponential, e, which is raised to the argument that is given. It is a library function belonging to the header, cmath.

g.

Explanation of Solution

Given: The value of PI is 3.14159 and E has the value 2.71828.

To find:Â That what will be the result of the function, max(2, min(3, 4)).

Solution:

The function, max(2, min(3,4)), will return the value 3. The min function returns the minimum of the parameters passed to the function. Whereas, the max function returns the maximum of the parameters passed. In the given condition, first the inner bracket will evaluate, so the min(3,4) will be 3. Then, the outer bracket will evaluate, so the max(2,3) will be 3. Thereby, making the final result to be 3.

h.

Explanation of Solution

Given: The value of PI is 3.14159 and E has the value 2.71828.

To find:Â That what will be the result of the function, sqrt(125.0).

Solution:

The function, sqrt(125.0), will evaluate to 11. The sqrt function is the function which helps in finding the square root of the parameter which is passed to the function. It is a library function belonging to the header, cmath.

i.

Explanation of Solution

Given: The value of PI is 3.14159 and E has the value 2.71828.

To find:Â That what will be the result of the function, ceil(-2.5).

Solution:

The function, ceil(-2.5), will return the value -2.0. It returns the smallest possible value which has to be either greater than or equal to the passed argument. It is a library function belonging to the header, cmath.

j.

Explanation of Solution

Given: The value of PI is 3.14159 and E has the value 2.71828.

To find:Â That what will be the result of the function, floor(-2.5).

Solution:

The function, floor(-2.5), will return the value -3.0. It will return the largest possible value which has to be either equal to or less than the passed argument. It is a library function belonging to the header, cmath.

k.

Explanation of Solution

Given: The value of PI is 3.14159 and E has the value 2.71828.

To find:Â That what will be the result of the function, asin(0.5).

Solution:

The function, asin(0.5), will return the value 0.52359. It returns the inverse of the sine of the angle which is passed as the parameter. It returns the value of the angle in radians. It is a library function belonging to the header, cmath.

l.

Explanation of Solution

Given: The value of PI is 3.14159 and E has the value 2.71828.

To find:Â That what will be the result of the function, acos(0.5).

Solution:

The function, acos(0.5), will return the value 1.04719. It returns the inverse of the cosine of the angle which is passed as the parameter. It returns the value of the angle in radians. It is a library function belonging to the header, cmath.

m.

Explanation of Solution

Given: The value of PI is 3.14159 and E has the value 2.71828.

To find:Â That what will be the result of the function, atan(1.0).

Solution:

The function, atan(1.0), will return the value 0.785398. It returns the inverse of the tangent of the angle which is passed as the parameter. It returns the value of the angle in radians. It is a library function belonging to the header, cmath.

n.

Explanation of Solution

Given: The value of PI is 3.14159 and E has the value 2.71828.

To find:Â That what will be the result of the function, ceil(2.5).

Solution:

The function, ceil(2.5), will return the value 3.0. It returns the smallest possible value which has to be either greater than or equal to the passed argument. It is a library function belonging to the header, cmath.

o.

Explanation of Solution

Given: The value of PI is 3.14159 and E has the value 2.71828.

To find:Â That what will be the result of the function, floor(2.5).

Solution:

The function floor, (2.5), will return the value 2.0. It will return the largest possible value which has to be either lesser than or equal to the passed argument. It is a library function belonging to the header, cmath.

p.

Explanation of Solution

Given: The value of PI is 3.14159 and E has the value 2.71828.

To find:Â That what will be the result of the function, log10(10.0).

Solution:

The function, log10(10.0), will return the value of 1. It returns the common base 10 logarithmic value of the argument which is passed inside. It is a library function belonging to the header, cmath.

q.

Explanation of Solution

Given: The value of PI is 3.14159 and E has the value 2.71828.

To find:Â That what will be the result of the function, pow(2.0, 3).

Solution:

The function, pow(2.0, 3), will return the value 8.0. It computes the base number which is raised to the power of the exponent number. It is a library function belonging to the header, cmath. It follows the syntax, pow(base, exponent).

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Chapter 4 Solutions

Introduction to Programming with C++

Chapter 4, Problem 11CP Chapter 4, Problem 12CP Chapter 4, Problem 13CP Chapter 4, Problem 14CP Chapter 4, Problem 15CP Chapter 4, Problem 16CP Chapter 4, Problem 17CP Chapter 4, Problem 18CP Chapter 4, Problem 19CP Chapter 4, Problem 20CP Chapter 4, Problem 21CP Chapter 4, Problem 22CP Chapter 4, Problem 23CP Chapter 4, Problem 24CP Chapter 4, Problem 25CP Chapter 4, Problem 26CP Chapter 4, Problem 27CP Chapter 4, Problem 28CP Chapter 4, Problem 29CP Chapter 4, Problem 30CP Chapter 4, Problem 1PE Chapter 4, Problem 2PE Chapter 4, Problem 3PE Chapter 4, Problem 4PE Chapter 4, Problem 5PE Chapter 4, Problem 6PE Chapter 4, Problem 7PE Chapter 4, Problem 8PE Chapter 4, Problem 9PE Chapter 4, Problem 10PE Chapter 4, Problem 11PE Chapter 4, Problem 12PE Chapter 4, Problem 13PE Chapter 4, Problem 14PE Chapter 4, Problem 15PE Chapter 4, Problem 16PE Chapter 4, Problem 17PE Chapter 4, Problem 18PE Chapter 4, Problem 19PE Chapter 4, Problem 20PE Chapter 4, Problem 21PE Chapter 4, Problem 22PE Chapter 4, Problem 23PE
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