Introduction to Java Programming and Data Structures, Comprehensive Version (11th Edition)
Introduction to Java Programming and Data Structures, Comprehensive Version (11th Edition)
11th Edition
ISBN: 9780134670942
Author: Y. Daniel Liang
Publisher: PEARSON
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Chapter 3.10, Problem 3.10.1CP
Explanation of Solution
Given statements:
(true) && (3>4)
- 1st part: The first part is given as "true".
- 2nd part: In the second part, the value "3" is not greater than "4". Hence the second part is "false".
- The AND (&&) operation becomes "true" if both the parts are "true". Otherwise, it is "false".
- Here, one part is "true" and the other part is "false".
Therefore, (true) && (3>4) returns "false"
!(x>0) && (x>0)
- Apply "1" in the place of "x". Then the statement becomes "!(1>0) && (1>0)"
- 1st part: In the first part, "1" is greater than "0". But NOT operator makes this as "false".
- 2nd part: In the second part, the value "1" is greater than "0". Hence the second part is "true".
- The AND (&&) operation becomes "true" if both the parts are "true". Otherwise, it is "false".
- Here, one part is "false" and the other part is "true".
Therefore, !(x>0) && (x>0)returns "false"
(x>0) || (x<0)
- Apply "1" in the place of "x". Then the statement becomes "(1>0) || (1<0)"
- 1st part: In the first part, "1" is greater than "0". Hence, it returns "true".
- 2nd part: In the second part, the value "1" is not less than "0". Hence the second part is "false".
- The OR (||) operation becomes "true" if any one of the parts is "true". Otherwise, it is "false".
- Here, one part is "true" and the other part is "false".
Therefore, (x>0) || (x<0) returns "true"...
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Chapter 3 Solutions
Introduction to Java Programming and Data Structures, Comprehensive Version (11th Edition)
Chapter 3.2, Problem 3.2.1CP Chapter 3.2, Problem 3.2.2CP Chapter 3.2, Problem 3.2.3CP Chapter 3.3, Problem 3.3.1CP Chapter 3.3, Problem 3.3.2CP Chapter 3.3, Problem 3.3.3CP Chapter 3.4, Problem 3.4.1CP Chapter 3.4, Problem 3.4.2CP Chapter 3.5, Problem 3.5.1CP Chapter 3.5, Problem 3.5.2CP
Chapter 3.5, Problem 3.5.3CP Chapter 3.6, Problem 3.6.1CP Chapter 3.6, Problem 3.6.2CP Chapter 3.6, Problem 3.6.3CP Chapter 3.6, Problem 3.6.4CP Chapter 3.7, Problem 3.7.1CP Chapter 3.7, Problem 3.7.2CP Chapter 3.9, Problem 3.9.1CP Chapter 3.10, Problem 3.10.1CP Chapter 3.10, Problem 3.10.2CP Chapter 3.10, Problem 3.10.3CP Chapter 3.10, Problem 3.10.4CP Chapter 3.10, Problem 3.10.5CP Chapter 3.10, Problem 3.10.6CP Chapter 3.10, Problem 3.10.7CP Chapter 3.10, Problem 3.10.8CP Chapter 3.10, Problem 3.10.9CP Chapter 3.10, Problem 3.10.10CP Chapter 3.10, Problem 3.10.11CP Chapter 3.11, Problem 3.11.1CP Chapter 3.12, Problem 3.12.1CP Chapter 3.13, Problem 3.13.1CP Chapter 3.13, Problem 3.13.2CP Chapter 3.13, Problem 3.13.3CP Chapter 3.13, Problem 3.13.4CP Chapter 3.13, Problem 3.13.5CP Chapter 3.14, Problem 3.14.1CP Chapter 3.14, Problem 3.14.2CP Chapter 3.14, Problem 3.14.3CP Chapter 3.14, Problem 3.14.4CP Chapter 3.15, Problem 3.15.1CP Chapter 3.15, Problem 3.15.2CP Chapter 3.15, Problem 3.15.3CP Chapter 3.15, Problem 3.15.4CP Chapter 3, Problem 3.1PE Chapter 3, Problem 3.2PE Chapter 3, Problem 3.3PE Chapter 3, Problem 3.4PE Chapter 3, Problem 3.5PE Chapter 3, Problem 3.6PE Chapter 3, Problem 3.7PE Chapter 3, Problem 3.8PE Chapter 3, Problem 3.9PE Chapter 3, Problem 3.10PE Chapter 3, Problem 3.11PE Chapter 3, Problem 3.12PE Chapter 3, Problem 3.13PE Chapter 3, Problem 3.14PE Chapter 3, Problem 3.15PE Chapter 3, Problem 3.16PE Chapter 3, Problem 3.17PE Chapter 3, Problem 3.18PE Chapter 3, Problem 3.19PE Chapter 3, Problem 3.20PE Chapter 3, Problem 3.21PE Chapter 3, Problem 3.22PE Chapter 3, Problem 3.23PE Chapter 3, Problem 3.24PE Chapter 3, Problem 3.25PE Chapter 3, Problem 3.26PE Chapter 3, Problem 3.27PE Chapter 3, Problem 3.28PE Chapter 3, Problem 3.29PE Chapter 3, Problem 3.30PE Chapter 3, Problem 3.31PE Chapter 3, Problem 3.32PE Chapter 3, Problem 3.33PE Chapter 3, Problem 3.34PE
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