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Chapter 12, Problem 1E

Explanation of Solution

Program Plan:

  • Import required package.
  • Define “CountFamiles”class.
    • Define main function.
      • Create object for scanner class.
      • Create array “incomeArr” by using “ArrayList”.
      • Display the prompt statement.
      • Assign “additionalValues” to “true”.
      • Initializes required variable.
      • Read input of income from user up to the value of “additionalValues” is “false”.
        • Display prompt statement for each family.
        • Read each family income from user and store it to “incomeValues”.
        • If “incomeValues” is less than “0”, then set “additionalValues” to “false”.
        • Otherwise, add the “incomeValues” to array “incomeArr”.
        • Increment the index.
      • Compute maximum income using “for” loop.
        • If “incomeArr.get(i)” is greater than maximum income, then assign maximum income to “incomeArr.get(i)”.
      • Display maximum income.
      • Display “10” percent of maximum income by “0.1 * maximumIncome”.
      • Initializes the count value to “0”.
      • Compute the count of families with incomes less than “10” percentage of maximum income using “for” loop.
        • Check condition. If value of “incomeArr.get(i)” is less than “0.1 * maximumIncome”, then increment count value and display the family income with less than “10” percentage of income by family wise.
      • Finally display the count of families.

Program:

The below java program is used to counts the number of families with less than “10” percent of maximum income using array.

“CountFamiles.java”

//Import required package

import java.util.*;

//Define "CountFamiles" class

public class CountFamiles

{

    //Define main function

    public static void main(String[] args)

    {

        //Create object for scanner class

        Scanner input = new Scanner(System.in);

/* Create array "incomeArr" by using "ArrayList" */

ArrayList<Double> incomeArr = new ArrayList<Double>();

        //Display the prompt statement

System.out.println("Enter the income for each family. Use a negative value to indicate the end ");

        //Assign "additionalValues" to "true"

        boolean additionalValues = true;

        //Initializes required variable

        int i = 0;

/* Read input of income from user upto the value of "additionalValues" is "false" */

        while(additionalValues)

        {

//Display prompt statement for each family

System.out.print("Enter Income for family " + (i +1) + ": ");

/* Read each family income from user and store it to "incomeValues" */

double incomeValues = input.nextDouble();

/* If "incomeValues" is less than "0", then */

            if(incomeValues < 0)

                /* Set "additionalValues" to "false" */

                additionalValues = false;

            /* Otherwise */

            else

/* Add the "incomeValues" to array "incomeArr" */

                incomeArr.add(incomeValues);

            //Increment the index

            i++;

        }

        //Compute maximum income using "for" loop

        double maximumIncome = incomeArr.get(0);

        for(i  = 0; i < incomeArr.size(); i ++)

        {

/* If incomeArr.get[i] is greater than maximum income, then */

            if(incomeArr.get(i) > maximumIncome)

//Assign maximum income to "incomeArr.get(i)"

                maximumIncome = incomeArr.get(i);

        }

        //Display maximum income

System.out.println("The maximum income is: " + maximumIncome);

        //Display 10 percent of maximum income

System.out.println("10% of maximum income is: " + (0.1 * maximumIncome));

        //Display prompt statement

System.out.println("\nDisplaying all families with incomes less than 10% of the maximum income income");

        //Initializes the count value to "0"

        int countValue = 0;

//Compute the count of families with incomes less than 10% of maximum income

        for( i=0; i<incomeArr.size(); i++)

        {

            //Check condition

if(incomeArr.get(i) < (0.1 * maximumIncome))

            {

                //Increment count value

                countValue++;

/* Display the family income with less than 10 percentage of income by family wise */

System.out.println("Family " + (i+1) + " had income " + incomeArr.get(i));

            }

        }

        //Display count of families

System.out.println("Count of families with 10% of maximum income is: " + countValue);

    }

}

Expert Solution & Answer
Check Mark
Sample Output

Output:

Enter the income for each family. Use a negative value to indicate the end

Enter Income for family 1: 10000

Enter Income for family 2: 48000

Enter Income for family 3: 20000

Enter Income for family 4: 12000

Enter Income for family 5: 300000

Enter Income for family 6: 40000

Enter Income for family 7: -1

The maximum income is: 300000.0

10% of maximum income is: 30000.0

Displaying all families with incomes less than 10% of the maximum income

Family 1 had income 10000.0

Family 3 had income 20000.0

Family 4 had income 12000.0

Count of families with 10% of maximum income is: 3

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Chapter 12 Solutions

Java: An Introduction to Problem Solving and Programming (8th Edition)

Chapter 12.1, Problem 12STQ Chapter 12.2, Problem 13STQ Chapter 12.2, Problem 14STQ Chapter 12.2, Problem 15STQ Chapter 12.2, Problem 16STQ Chapter 12.3, Problem 17STQ Chapter 12.3, Problem 18STQ Chapter 12.3, Problem 19STQ Chapter 12.3, Problem 20STQ Chapter 12.3, Problem 21STQ Chapter 12.3, Problem 22STQ Chapter 12.3, Problem 23STQ Chapter 12.3, Problem 24STQ Chapter 12.3, Problem 25STQ Chapter 12.3, Problem 26STQ Chapter 12.3, Problem 27STQ Chapter 12.3, Problem 28STQ Chapter 12.4, Problem 29STQ Chapter 12.4, Problem 30STQ Chapter 12.5, Problem 31STQ Chapter 12.5, Problem 32STQ Chapter 12, Problem 1E Chapter 12, Problem 2E Chapter 12, Problem 3E Chapter 12, Problem 4E Chapter 12, Problem 5E Chapter 12, Problem 6E Chapter 12, Problem 7E Chapter 12, Problem 8E Chapter 12, Problem 9E Chapter 12, Problem 10E Chapter 12, Problem 12E Chapter 12, Problem 13E Chapter 12, Problem 14E Chapter 12, Problem 15E Chapter 12, Problem 17E Chapter 12, Problem 1P Chapter 12, Problem 2P Chapter 12, Problem 3P Chapter 12, Problem 4P Chapter 12, Problem 5P Chapter 12, Problem 1PP Chapter 12, Problem 2PP Chapter 12, Problem 3PP Chapter 12, Problem 9PP Chapter 12, Problem 10PP Chapter 12, Problem 11PP Chapter 12, Problem 12PP Chapter 12, Problem 13PP Chapter 12, Problem 14PP Chapter 12, Problem 15PP

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