ython implements Newton's algorithm for finding the square root of a number using recursion NOTE: n = 17 # we want the square root of 17 for example g = 4 # our guess is 4 initially error = 0.0000000001 # we want to stop when we are this close while abs(n - (g**2)) > error: g = g - ((g**2 - n)/(2 * g)) # g holds the square root of n at this point Implement this algorithm in a function sqRoot(n), that returns the square root using recursion your code to return the square root of n to an accuracy within the error e, using Newton's algorithm with an initial guess of g def sqRoot(n, g, e):

Assignment-2-162-sumer 22.000X 5.0 KB) ZOOM 5. Palindrome Detector A palindrome is any word, phrase, or sentence that reads the same forward and backward. Here are some well-known palindromes: Able was I, ere I saw Elba A man, a plan, a canal, Panama Desserts, I stressed Kayak Write a boolean method that uses recursion to determine whether a string argument is a palindrome. The method should return true if the argument reads the same forward and backward. Demonstrate the method in a program.

Python Using recursion only! No loops or global var! return the largest number not print! Using such len(), isdigit() def getMaxDigit(phrase):

please code in python, correct the code please def solution(S): result = [] word_counts = {} for i, word in enumerate(S): sorted_word = ''.join(sorted(word)) if sorted_word in word_counts: word_counts[sorted_word].append(i) else: word_counts[sorted_word] = [i] for word in S: sorted_word = ''.join(sorted(word)) indices = word_counts[sorted_word] result.append(indices[0]) # Update word_counts to remove the used index only if it has more than one index if len(indices) > 1: word_counts[sorted_word] = indices[1:] return result s = ["abc", "bca", "dbe"]result = solution(s)print(result) this is the expected output: # Output: [0, 2, 1]I am getting [0,1,2]

%matplotlib inline import numpy as np from matplotlib import pyplot as plt import math

Complete the following program Multiply.java. This program uses recursion to multiply two numbers through repeated addition. The output should look exactly like what is pictured below. The code should be completed where it states "complete here"

PYTHON! Can someone explain this recursion problem? In my mind the ouput would be 19 because: 1st step: R(5) = -1 because (5-1)-5 then returns to top with -1 and since that is less than zero it returns 20 but subtracts the -1 it returned def R(n): if n<=0: return 20 return R(n-1) - n print(R(5))

Please help with this question. Your assistance is greatly appreciated.

n-1 Geometric (n) = i=1 i=1 1 1 * n-1 П %3D Harmonic (n) = i=1 n Let's look at examples. If we use n = 4, the geometric progression would be 1 * 2 * 3 * 4 = 24, and the harmonic 1.1.1 1 progression would be 1* -= 0.04166. 2 3 4 24 Task #1 Tracing Recursive Methods 1. Copy the file Recursion.java (see Code Listing 16.1) from the Student Files or as directed by your instructor. 2. Run the program to confirm that the generated answer is correct. Modify the factorial method in the following ways: a. Add these lines above the first if statement: int temp; System.out.println ("Method call -- " + "calculating " "Factorial of: " + n); + Copyright © 2019 Pearson Education, Inc., Hoboken NJ b. Remove this line in the recursive section at the end of the method: return (factorial (n - 1) * n); c. Add these lines in the recursive section: temp = factorial (n - 1); System.out.println ("Factorial of: " (n - 1) + " is " temp); return (temp * n); 3. Rerun the program and note how the recursive calls...

Using recursion, write a Java program that takes an input ‘n’ (a number) from a user to calculate and print out the Fibonacci using the following modified definition: F(N) = 1 if n = 1 or n = 2 = F((n+1)/2)2 + F((n-1/2)2 if n is odd = F(n/2 + 1)2 – F(n/2 – 1)2 if n is even Your solution must implement recursion to receive points for this question.

Answer 12....

The following code implements Newton's algorithm for finding the square root of a number using repetition: n = 17 # we want the square root of 17 for exampleg = 4 # our guess is 4 initiallyerror = 0.0000000001 # we want to stop when we are this closewhile abs(n - (g**2)) > error: g = g - ((g**2 - n)/(2 * g))# g holds the square root of n at this point Implement this algorithm in a function sqRoot(n), that returns the square root using recursion. Assume that the function will be called with positive numbers only. Note: Your initial guess cannot be zero!

How can I apply this python code wherein I have an input n. Then create a list from 2, n and remove the multiples of n. Example: Input: 10 Output: 2, 3, 4, 5, 6, 7, 8, 9 def createList(n): #Base Case/s #TODO: Add conditions here for your base case/s #if <condition> : #return <value> #Recursive Case/s #TODO: Add conditions here for your recursive case/s #else: #return <operation and recursive call> #remove the line after this once you've completed all the TODO for this function return [] def removeMultiples(x, arr): #Base Case/s #TODO: Add conditions here for your base case/s #if <condition> : #return <value> #Recursive Case/s #TODO: Add conditions here for your recursive case/s #else: #return <operation and recursive call> #remove the line after this once you've completed all the TODO for this function return []