Database System Concepts
Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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[画像:can you please convert this python code into java? Python code is as shown below: # recursive function def row_puzzle_rec(row, pos, visited): # if the element at the current position is o we have reached our goal if row[pos] == 0: possible = True else: # make a copy of the visited array visited visited[:] # if the element at the current position has been already visited then it's a loop. # as then its not possible to reach the last element, set possible to False if visited[pos]: possible = False else: #set visitied for the element as True visited[pos] = True possible = False # if its possible to move left then recurse in the left direction if pos - row[pos]>o and row_puzzle_rec(row, pos - row[pos], visited): # return immediately if the goal is reached return True # if its possible to move right then recurse in the right direction if pos + row[pos] < len(row) and row_puzzle_rec(row, pos + row[pos], visited): # return immediately if the goal is reached. return True return possible def row_puzzle(row): #visited array will be used to check if a particular element was visited # initialize the array to False visited = [False for item in range(len(row))] #second argument is the token position initialized to o return row_puzzle_rec(row, o, visited) possible = row_puzzle([2, 4, 5, 3, 1, 3, 1, 4, ol) print(possible) possible = row_puzzle([1, 3, 2, 1, 3, 4, 0]) print(possible)]
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Transcribed Image Text:can you please convert this python code into java? Python code is as shown below: # recursive function def row_puzzle_rec(row, pos, visited): # if the element at the current position is o we have reached our goal if row[pos] == 0: possible = True else: # make a copy of the visited array visited visited[:] # if the element at the current position has been already visited then it's a loop. # as then its not possible to reach the last element, set possible to False if visited[pos]: possible = False else: #set visitied for the element as True visited[pos] = True possible = False # if its possible to move left then recurse in the left direction if pos - row[pos]>o and row_puzzle_rec(row, pos - row[pos], visited): # return immediately if the goal is reached return True # if its possible to move right then recurse in the right direction if pos + row[pos] < len(row) and row_puzzle_rec(row, pos + row[pos], visited): # return immediately if the goal is reached. return True return possible def row_puzzle(row): #visited array will be used to check if a particular element was visited # initialize the array to False visited = [False for item in range(len(row))] #second argument is the token position initialized to o return row_puzzle_rec(row, o, visited) possible = row_puzzle([2, 4, 5, 3, 1, 3, 1, 4, ol) print(possible) possible = row_puzzle([1, 3, 2, 1, 3, 4, 0]) print(possible)
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