Write a while loop to read positive integers from input until a non-positive integer is read. For each positive integer read before the non-positive integer, add the positive integer plus five to vector vect1. Ex: If the input is 9 1 2 8 -999, then the output is: 14 6 7 13 Note: Positive integers are greater than 0. 1 #include 2 #include 3 using namespace std; 4 5 int main() { 6 7 8 9 10 11 12 13 14 15 16 17} vector vect1; int value; int i; V* Your code goes here */ for (i = 0; i < vect1.size(); ++i) { cout << vect1.at (i) << endl; } return 0;

In C++, define an integer vector and ask the user to give you values for the vector. Because you used a vector, so you don't need to know the size. user should be able to enter a number until he wants(you can use while loop for termination. for example if the user enters any negative number, but until he enters a positive number, your program should read and push it inside of the vector). the calculate the average of all numbers he entered.

Please complete the following functions: 1. int loadDictionary(istream& dictfile, vector<string>& dict) 2. int permute(string word, vector<string>& dict, vector<string>& results) 3. void display(vector<string>& results)

# dates and times with lubridateinstall.packages("nycflights13") library(tidyverse)library(lubridate)library(nycflights13) Qustion: Create a function called date_quarter that accepts any vector of dates as its input and then returns the corresponding quarter for each date Examples: "2019年01月01日" should return "Q1" "2011年05月23日" should return "Q2" "1978年09月30日" should return "Q3" Etc. Use the flight's data set from the nycflights13 package to test your function by creating a new column called quarter using mutate()

Complete the code below to display all values inside the customers_per_hour std::vector. Display each value in a separate line (using std::endl or "\n"). #include #include int main() { std::vector customers_per_hour {2, 4, 1, 4, 3, 2, 1, 1}; for (int customers : customers_per_hour) { std::cout << customers << "\n"; } return 0; } #include #include int main() { std::vector customers_per_hour {2, 4, 1, 4, 3, 2, 1, 1}; for (int customers : customers_per_hour) { std::cout << customers << "\n"; } return 0; } #include #include int main() { std::vector customers_per_hour {2, 4, 1, 4, 3, 2, 1, 1}; for (int customers : customers_per_hour) { std::cout << customers << "\n"; } return 0; }

c++

Write the following function #input: a numerical vector x #output:the normalized vector, i.e. the vector rescaled into [0,1] # the formula to normalize is (x-min(x))/ (max(x)-min(x)) # you can NOT use the functions min and max # you can use %%, nrow, ncol, and length # you can write multiple functions

#include <iostream> #include <string> using namespace std; int main() { // Declare a named constant for array size here // Declare array here // Use this integer variable as your loop index int loopIndex; // Use this variable to store the batting average input by user double battingAverage; // Use these variables to store the minimim and maximum values double min, max; // Use these variables to store the total and the average double total, average; // Write a loop to get batting averages from user and assign to array cout << "Enter a batting average: "; cin >> battingAverage; // Assign value to array // Assign the first element in the array to be the minimum and the maximum min = averages[0]; max = averages[0]; // Start out your total with the value of the first element in the array total = averages[0]; // Write a loop here to access array values starting with...