3. Use the input function to ask the user for a positive, whole number. Then use a for loop to generate a vector containing as many elements of the following sequence as the user requested. For example, if the user entered 7 then your program should generate a vector containing: 1/2 3/4 5/6 7/8 9/10 11/12 13/14 The numerator of the sequence starts at 1 and is always odd. The denominator starts at 2 and is always even. Both the numerator and denominator go up by two each time.

Can you please use python code and explain it please

(1) Prompt the user to input five pairs of numbers: A player's jersey number (0 - 99) and the player's rating (1 - 9). Store the jersey numbers in one int vector and the ratings in another int vector. Output these vectors (i.e., output the roster). Ex: Enter player 1's jersey number: 84 Enter player 1's rating: 7 Enter player 2's jersey number: 23 Enter player 2's rating: 4 Enter player 3's jersey number: 4 Enter player 3's rating: 5 Enter player 4's jersey number: 30 Enter player 4's rating: 2 Enter player 5's jersey number: 66 Enter player 5's rating: 9 ROSTER Player 1 -- Jersey number: 84, Rating: 7 Player 2 -- Jersey number: 23, Rating: 4 ... (2) Implement a menu of options for a user to modify the roster. Each option is represented by a single character. Following the initial 5 players' input and roster output, the program outputs the menu. The program should also output the menu again after a user chooses an option. The program ends when the user chooses the option to Quit. For...

Produce the following program. Series 1

Produce the following program. Series 8

Produce the following program. Series 3

c++

Integers are read from input and stored into a vector until 0 is read. If the vector's last element is odd, output the odd elements in the vector. Otherwise, output the even elements in the vector. End each number with a newline. Ex: If the input is -9 12 -6 1 0, the vector's last element is 1. Thus, the output is: -9 1 Note: (x % 2 != 0) returns true if x is odd. int value; int i; bool isodd; 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 } cin>> value; while (value != 0) { } for (i = 0; i> value; Check return 0; 1 Next level 2 X 1: Compare output 3 4 For input -9 12 -6 1 0, the vector elements are -9, 12, -6, and 1. The last element, 1, is odd. The odd elements in the vector, -9 and 1, are output, each on a new line. Not all tests passed. 2 V 3

Integers are read from input and stored into a vector until 0 is read. If the vector's last element is odd, output the odd elements in the vector. Otherwise, output the even elements in the vector. End each number with a newline. Ex: If the input is -9 12 -6 1 0, the vector's last element is 1. Thus, the output is: -9 1 Note: (x % 2!= 0) returns true if x is odd. 4 5 int main() { 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20} vector vect1; int value; int i; bool isodd; cin>> value; while (value != 0) { vect1.push_back(value); cin>> value; } V* Your code goes here */ return 0; 2 3

I need to write a program named Search.java that uses a function called search_string to check whether a string exists in the array or not. 1- The array of strings is iterated using a for loop and the value at every index is compared with the value to be searched in the array. 2- A boolean variable is set if any array value matches with the string. 3- At the end of the loop, this boolean variable is checked to determine if the array contains the string. It may be necessary to import java.util.Arrays then use Arrays.toString, String equals(). Output should be as picture shows